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Usimov [2.4K]
2 years ago
9

HELP PLEASE!!!! WHO WANTS BRAINLEST!!b

Mathematics
1 answer:
marin [14]2 years ago
5 0

Answer:

3/13

Step-by-step explanation:

number of balloons that are green AND shaped like a dog (3) over the TOTAL number of balloons (13)

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What is the median of the data set 11,13,15,21,23,31,31,33?<br> A. 31<br> B. 21<br> OC. 23<br> D. 22
SSSSS [86.1K]

Median:

The median in this set is the 5th term.

Therefore the median in this set is 23.

3 0
3 years ago
Suppose that a family wants to start a college fund for their child. If they can get a rate of 5.5% , compounded monthly, and wa
Angelina_Jolie [31]
In 20 years a family will be able to earn 35 450 dollars. The interest that they earned is 5.5% compounded monthly. Now, let's find out how much will they need to save monthly to get this amount in 20 year:
=> 12 * 20 = 240 months
=> 35 450 / 240 months = 147.7 dollars per month is the money with interest
Let's subtract the interest
=> 147.7 * 0.055 = 8.1 dollars.
=> 147.7 - 8.1 = 139.6 dollars per month.

3 0
4 years ago
Read 2 more answers
Can somebody please help me with this
valentina_108 [34]
Your answer is A if i did my calculations correct. go with A!
4 0
3 years ago
Read 2 more answers
Show that W is a subspace of R^3.
musickatia [10]

Answer:

Check the two conditions of Subspace.

Step-by-step explanation:

If W is a Subspace of a vector space, V then it should satisft the following conditions.

1) The zero element should be in W.

Zero element can be different for different vector spaces. For examples, zero vector in $ \math{R^2} $ is (0, 0) whereas, zero element in $ \math{R^3} $ is (0, 0 ,0).

2) For any two vectors, $ w_1 $ and $ w_2 $ in W, $ w_1 + w_2 $ should also be in W.

That is, it should be closed under addition.

3) For any vector $ w_1 $ in W and for any scalar, $ k $ in V, $ kw_1 $ should be in W.

That is it should be closed in scalar multiplication.

The conditions are mathematically represented as follows:

1) 0$ \in $ W.

2) If $ w_1 \in W; w_2 \in W $ then $ w_1 + w_2 \in W $.

3) $ \forall k \in V, and \hspace{2mm} \forall w_1 \in W \implies kw_1 \in W

Here V = $ \math{R^3} $ and W = Set of all (x, y, z) such that $ x - 2y + 5z = 0 $

We check for the conditions one by one.

1) The zero vector belongs to the subspace, W. Because (0, 0, 0) satisfies the given equation.

i.e., 0 - 2(0) + 5(0) = 0

2) Let us assume $ w_1 = (x_1, y_1, z_1) $ and $ w_2 = (x_2, y_2, z_2) $ are in W.

That means: $ x_1 - 2y_1 + 5z_1 = 0 $ and

$ x_2 - 2y_2 + 5z_2 = 0 $

We should check if the vectors are closed under addition.

Adding the two vectors we get:

$ w_1 + w_2 = x_1 + x_2 - 2(y_1 + y_2) + 5(z_1 + z_2) $

$ = x_1 + x_2 - 2y_1 - 2y_2 + 5z_1 + 5z_2 $

Rearranging these terms we get:

$ x_1 - 2y_1 + 5z_1 + x_2 - 2y_2 + 5z_2 $

So, the equation becomes, 0 + 0 = 0

So, it s closed under addition.

3) Let k be any scalar in V. And $ w_1 = (x, y, z) \in W $

This means $ x - 2y + 5z = 0 $

$ kw_1 = kx - 2ky + 5kz $

Taking k common outside, we get:

$ kw_1 = k(x - 2y + 5z) = 0 $

The equation becomes k(0) = 0.

So, it is closed under scalar multiplication.

Hence, W is a subspace of $ \math{R^3} $.

7 0
3 years ago
I am totally confused with this question, please help​
lapo4ka [179]

a) CE = 16 ft

b) BC = 6√2 ft [ BY Pythagoras theorem]

c) m angle CFD = 90°

d) m angle DBE = 90°

8 0
3 years ago
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