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Simora [160]
3 years ago
11

The time to replace vehicle wiper blades at a service center was monitored using a mean and a range chart. six samples of n = 20

observations have been obtained and the sample means and ranges computed:
Business
2 answers:
Lilit [14]3 years ago
5 0

Explanation:

The complete question statement is given;

The time to replace vehicle wiper blades at a service center was monitored using a mean and a range chart. six samples of n = 20 observations have been obtained and the sample means and ranges computed:

Sample Mean Range Sample Mean Range

1 3.06 .42

2 3.15 .50

3 3.11 .41

4 3.13 .46

5 3.06 .46

6 3.09 .45

Determine the upper limits for the mean

Determine the lower control limit for the mean

Solution

To determine, the upper limit and the lower limit, we need to first find the average of the mean for six sample

Mean average = 3.1

Range average = 0.45

Now for the upper limit; the formula is

= Mean Average + 0.18 (Range average)

= 3.1 + 0.18 (0.45)

=3.181

Now for the lower limit; the formula is

= Mean Average - 0.18 (Range average)

= 3.1 - 0.18 (0.45)

=3.01

morpeh [17]3 years ago
3 0

Answer:

control limits for X (mean time) = 3.1 +/- 0.081 or (3.181 ; 3.019)

control limits for R (range) = (0.1845 ; 0.711)

Explanation:

Sample              Mean             Range

1                         3.06                 0.42

2                        3.15                  0.50

3                        3.11                   0.41

4                        3.13                  0.46

5                        3.06                 0.46

6                        3.09                 0.45

average             3.10                 0.45

to determine the upper and lower limits we need to find z in table for R charts, and look at the 20th value for A₂, D₃ and D₄:

  • z for A₂ (n = 20) = 0.18
  • z for D₃ (n = 20) = 0.41
  • z for D₄ (n = 20) = 1.59

control limits for X = average mean +/- z(A₂) x average range

control limits for X = 3.1 +/- (0.18 x 0.45)

control limits for X = 3.1 +/- 0.081 or (3.181 ; 3.019)

now the control limits for R (range):

lower control limit = D₃ x average range = 0.41 x 0.45 = 0.1845

upper control limit = D₄ x average range = 1.59 x 0.45 = 0.711

control limits for R (range) = (0.1845 ; 0.711)

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Answer:

10%Corridor

2011 $0

2012 $250,000

2013 $295,000

2014 $360,000

Accumulated

2011 $0

2012 $280,000

2013 $367,000

2014 $372,000

Minimum Amortization of Loss

2011 $0

2012 $3,000

2013 $6,000

2014 $1,000

Explanation:

Calculation to determine the net gain or loss amortized and charged to pension expense under the corridor approach

Year, Projected Benefit Obligation (a) , Plan Assets, 10%Corridor, Accumulated d OCI (G/L) (a), Minimum Amortization of Loss

2011 $2,000,000 $1,900,000 $200,000 $ 0 $0

2012 $2,400,000 $2,500,000 $250,000 $280,000 $3,000(b)

2013 $2,950,000 $2,600,000 $295,000 $367,000(c) $6,000(d)

2014 $3,600,000 $3,000,000 $360,000 372,000(e) $1,000(f)

Calculation for 10%Corridor

2011 $0

2012 10%*$2,500,000 =$250,000

2013 10%*$2,950,000 =$295,000

2014 10%*$3,600,000 =$360,000

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a. As at the beginning of the year

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d. ($367,000 – $295,000) ÷ 12 years = $6,000

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f ($372,000 – $360,000) ÷ 12 years = $1,000

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2012 $250,000

2013 $295,000

2014 $360,000

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2013 $367,000

2014 $372,000

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2012 $3,000

2013 $6,000

2014 $1,000

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