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scoundrel [369]
2 years ago
13

How would I solve this problem?

Mathematics
1 answer:
Nataliya [291]2 years ago
3 0

The area of the garden enclosed by the fencing is

A(x, y) = xy

and is constrained by its perimeter,

P = x + 2y = 200

Solve for x in the constraint equation:

x = 200 - 2y

Substitute this into the area function to get a function of one variable:

A(200 - 2y, y) = A(y) = 200y - 2y²

Differentiate A with respect to y :

dA/dy = 200 - 4y

Find the critical points of A :

200 - 4y = 0   ⇒   4y = 200   ⇒   y = 50

Compute the second derivative of A:

d²A/dy² = -4 < 0

Since the second derivative is always negative, the critical point is a local maximum.

If y = 50, then x = 200 - 2•50 = 100. So the farmer can maximize the garden area by building a (100 ft) × (50 ft) fence.

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2x+3y=9<br> 2x+y=7<br> simultaneous equation
Marat540 [252]

Answer:

x=3 and y=1

Step-by-step explanation:

subtract equation 2 from 1

then (2x+3y) -(2x+y) =9-7

2x-2x+3y-y =2

2y=2 therefore y=1

substitute y value in 2x+y=7

2x+1=7

2x=7-1

2x=6

x=3

3 0
3 years ago
Name the set(s) of numbers to which -10 belongs.
NeX [460]
-10 belongs to integers, rational numbers, and real numbers.
6 0
3 years ago
Read 2 more answers
Find the x- and y-intercepts of the graph of 4x + 10y = 36. State your answers as
svetoff [14.1K]

Answer:

Step-by-step explanation:

Family.

3 0
3 years ago
Ok umm whoever this katie girl is she is making me real mad like fr she has deleted most of my answers because after i answer i
alisha [4.7K]
Yea it isss like omg
7 0
3 years ago
PLZ HEEEELP!!!!! 10 POINTS!!!!
katrin2010 [14]

Answer:

Step-by-step explanation:

Part a

We need two inequalities, one for time worked at each job and the other

for amounts of money earned.

time:  Let b and c represent the time (number of hours) worked at babysitting and landscaping respectively.  Then b + c ≤ 20 hrs/wk

earnings:  Let ($3/hr)(b) represents the amount of money earned babysitting for b hour.  Let  ($7/hr)(c) represent the money earned working at landscaping.  These amounts are <em>per week</em>.  The appropriate inequality is  ($3/hr)(b) +  ($7/hr)(c) ≥ $84 per week.  The other inequality is

b + c ≤ 20 hrs/wk.

Part b:

As before, b + c ≤ 20 hrs/wk.  What happens if Chet spends all his 20 hours babysitting?  To answer this, set c = 0 (no landscaping hours).  Then b ≤ 20 hours.  At $3/hr, he could earn only $60 and have no time left for landscaping.  Not good.

Let's experiment:  suppose he works 15 hours babysitting and 5 hours landscaping.  His earnings would be $45 + $35, or $80.  Still not enough; he wants to earn $84 total.    Let's redistribute his time and try again:  suppose he works 14 hours babysitting and 6 hours landscaping; his earnings would be $42 + $42, or $84.  So {b = 14 hours and c + 6 hours} is a solution.  As we continue to reduce the number of hours Chet works babysitting and correspondingly increase those he works landscaping, his earnings will go up, beyond $84.

Here's a table that summarizes this:

babysitting          landscaping    total amount

  hours                   hours               earned

      15                          5                      $60 (not acceptable)

       14                         6                       $84 (borderline acceptable)

       12                          8                       $36 + $42 = $78 (great)

        6                          14                       $116 (greater still)

         2                          18                     $132

          1                           19                      $134

          0                          20                      $140

Summary:  Chet can work anywhere from 0 to 14 hours babysitting and expect to earn $84 or more.

4 0
3 years ago
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