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2 years ago

Which statement about a right triangle is NOT true

Mathematics

1 answer:

nlexa [21]2 years ago

8 0

Answer:

The sum of the length of the two legs is equal to the length of the hypotenuse.

You might be interested in

Find the difference: -2/5-(-4/5)

CaHeK987 [17]

Answer:

2/5

Step-by-step explanation:

-2/5-(-4/5) (remove the parentheses)

-2/5+4/5 (calculate)

solution: 2/5

hope this helps!

5 0

3 years ago

There are 450 computer's in a technology store. Alex Bought 231 of them for school. Each one was $230. He has $10,000. How much

stepan [7]

231 x 230 = 53,130
mans in negatives

8 0

2 years ago

How much less would a 23-year-old female pay for a $25,000 policy of 20 year life insurance (@ $2.90 per $1000) than straight li

mojhsa [17]

<u>Answer</u>:

The female would pay $322.00 less for a policy of $25,000

<u>Step-by-step explanation:</u>

Since we have given that

Amount for policy = $25000

If she opt for 20 year life insurance at $2.90 per $1000.

so, her amount of premium becomes

$25000\times \frac{2.9}{1000}$

=$72.50

If she opt for straight life insurance at $15.78 per $1000,

Then, her amount of premium becomes

$25000 \times \frac{15.78}{1000}$

= $394.50

Difference between them is given by

$394.50-$72.5 = $322.00

5 0

3 years ago

Read 2 more answers

Divide 20 by the difference of 14 and 9.

vekshin1

The answer is 4 because 14-9=5 and 20/5=4

6 0

3 years ago

Read 2 more answers

Can someone pls help me find the second derivative of this. I need to find the concave up and down intervals but I’m having trou

KonstantinChe [14]

Starting from

$f(x)=\dfrac14(x+1)^{\frac83}-4(x+1)^{\frac23}$

take the first derivative using the power and chain rules:

$f'(x)=\dfrac83\cdot\dfrac14(x+1)^{\frac83-1}-\dfrac23\cdot4(x+1)^{\frac23-1}$

$f'(x)=\dfrac23(x+1)^{\frac53}-\dfrac83(x+1)^{-\frac13}$

Now take the second derivative:

$f''(x)=\dfrac53\cdot\dfrac23(x+1)^{\frac53-1}-\left(-\dfrac13\right)\cdot\dfrac83(x+1)^{-\frac13-1}$

$f''(x)=\boxed{\dfrac{10}9(x+1)^{\frac23}+\dfrac89(x+1)^{-\frac43}}$

Optionally, you can condense the second derivative a bit by factoring out $\frac89(x+1)^{-\frac43}$ , which gives

$f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^{\frac63}+1\right)$

$f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^2+1\right)$

$f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80x^2+160x+81\right)$

3 0

3 years ago