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2 years ago

What is the closest whole number approximation of √50?

Mathematics

2 answers:

mr_godi [17]2 years ago

6 0

Answer:

Step-by-step explanation:

√50 is close to √49

49 is a perfect square, 50 is close to 49.

√49 = 7

√50 ≈ 7.071068

mojhsa [17]2 years ago

4 0

Answer:

Step-by-step explanation:

$\sqrt{50} =7.07$

Hope this helps

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each baseball team has 9 players and each football team has 11 players. 6 schools have both baseball and football teams. Four sc

adelina 88 [10]

Answer:

156 players

Step-by-step explanation:

The 9 players for baseball and 11 players for football are added. 9 + 11 = 20.

Once you have 20, you can multiply it by the 6 schools. Which gets you 120 players so far.

After you multiply the 4 schools by the 9 players for baseball. You’ll get 36. Add the 120 players to 36 players and you’ll get 156 players for the 10 schools in total

6 0

3 years ago

In questions 1a-1d, choose yes or no to tell if the number 1/2 will make each equation true.

Tresset [83]

Answer:

Step-by-step explanation:

1a = yes

1b = no, you don’t add the denominators together when adding.

1c = yes

1d = yes

4 0

3 years ago

In DCAB, if ÐB = 38', What is ÐC?

frutty [35]

180-38= 142. So your answer would be 142 for dc.

7 0

3 years ago

find the value of x of given figure and solve this question step by step plzz help question number D

Alinara [238K]

Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

So in BDC

$Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm$

Applying Pythagoras theorem:

$(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm$

Solving for triangle ABC

$Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\$

Applying Pythagoras theorem

$AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm$

Hence,

x=15 cm

8 0

2 years ago

Which line is parallel to the line y = 3x + 6?

TiliK225 [7]

Y = 3x - 9, because for a line to be parallel it has to have the same gradient (x value) as the first line, and y = 3x - 9 is the only equation with the x value of 3.

7 0

3 years ago