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1 year ago

Using the digits 0 to 9

Mathematics

1 answer:

Gre4nikov [31]1 year ago

8 0

Supplementary Angles:

$\boxed{100°} and \boxed{80°}$

Arithmetically speaking, the closest 2 supplementary angles can get (in 3 and 2 digits respectively) is the upwritten.

Complementary Angles:

$\boxed{45°} and \boxed{45°}$

Simply, in this case, for angles to be numerically as close as possible - make both the angles 45°.

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Solve for the value of v: V+27=117

Fudgin [204]

V+27=117
Subtract 27 to 117:
v=90

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2 years ago

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Ariane borrows $300 on a 5−year loan. She is charged 5% simple interest per year. How much interest is she charged for 5 years?

AnnyKZ [126]

Answer:

Interest = $75

Total to pay back = $375

Step-by-step explanation:

The total amount she will have to pay back is found by the formula:

= Amount borrowed * (1 + rate * years)

= 300 * ( 1 + 5% * 5)

= $375

The interest is therefore:

= Amount to be paid back - Amount borrowed

= 375 - 300

= $75

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2 years ago

Cady found that she uses 1/6 of a roll of paper towels each week. How many rolls of paper towels will she use in 8 weeks?

KonstantinChe [14]

Answer:

$1 \frac{2}{6}$

Step-by-step explanation:

$8 \times \frac{1}{6 } = \frac{8}{6} = 1 \frac{2}{6}$

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2 years ago

One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many

Phantasy [73]

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = $6.022\times 10^{23}$ sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

$\frac{6.022\times 10^{23}}{10^{12}}=6.022\times 10^{11}$

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of $6.022\times 10^{11}$ trillion sand particles is

$Mass=1000\times 6.022\times 10^{11}=6.022\times 10^{14}tonnes$

Part 2)

Since it is given that volume of 1 sand particle is $1.0mm^{3}$ thus the volume of 1 mole of sand is volume of $6.022\times 10^{23}$ sand particles

Thus volume of 1 mole is $V=1.00\times 10^{-18}km^{3}\times 6.022\times 10^{23}=6.022\times 10^{5}km^{3}$

Now since the Area of united states is $A=3.6\times 10^{6}mile^{2}=5.8\times 10^{6}km^{2}$

Thus the depth of the sand pile is

$Depth=\frac{Volume}{Area}=\frac{6.022\times 10^5}{5.8\times 10^6}=0.10387km=103.8meters$

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2 years ago

A teacher listed 28,30,32 and 36 as ages of the students in his class with frequencies 8,10,5 and 7 Respect Respectively.......

Margaret [11]

gawd daym that's a lot of students

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2 years ago

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Using the digits 0 to 9 ​

Using the digits 0 to 9