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2 years ago

Seven cakes cost £2.10 how much do 10 cakes cost

1 answer:

7 0

Ten cakes costs $2.19 (pounds, but I don't have a pounds symbol on my computer) because if you divide $2.10 by seven you get $0.3, and if you add 3×0.3 (because we have seven, and we need to add three more to get ten) we get $0.9.

0.9+2.10=2.19

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What is the product of the fractions below? 6/11 times 7/3

WARRIOR [948]

Answer:

1 and 27/100

Hope this helps

6 0

2 years ago

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What is the sum of the finite arthemetic series (-10)+0+10+20....+130

Ganezh [65]

That would be 20,30,40,50,60,70,80,90,100,110,120,130. 200,150,300,250
650 + 250 = so the answer would be 900.

4 0

3 years ago

A theater has 30 seats in the first row. Each row behind the first row

Lana71 [14]

Answer:

a, Row 1 = 30 seats

Row 2 = 32 seats

Row 3 = 34 seats

Row 4 = 36 seats

b, n + equidistant number of seats added each row (2) * number of row - 1

c, 58 seats

Step-by-step explanation:

a, Because the seats is increasing by 2 after every row after row 1

Therefore, row 2 = row 1 + 2 = 30+2 = 32 seats

Row 3 = Row 2 + 2 =32+2 =34 seats

Row 4 = Row 3 + 2 = 34 + 2 = 36 seats

b, The explicit rule for the number of seats would be:

Row 1 = n

Row 2 = n + equidistant number of seats added each row (2) * (2-1) = n + 2

Row 3 = n+ equidistant number of seats added each row (2) * (3-1) = n+ 4

Row 4 = n + equidistant number of seats added each row(2) * (4-1) = n+6

etc.....

c, The number of seats in the 15th row would be = number of seat in the first row + equidistant number of seats added each row * 15 - 1 (first row)

= 30 + 2 * 14= 30 + 28 = 58 seats

Hope this help you :3

6 0

2 years ago

Read 2 more answers

At the beginning of the first day, Ann has 25 dollars. By the end of the first day, Ann has 2/3 of the money that she had at the

ira [324]

Answer:

Ann have at the end of the second day $\$9\frac{11}{21}.$

Step-by-step explanation:

Given:

At the beginning of the first day, Ann has 25 dollars.

By the end of the first day, Ann has 2/3 of the money that she had at the beginning of the first day.

By the end of the second day, Ann has 4/7 of the money that she had at the end of the first day.

Now, to find the money Ann have at the end of the second day.

Ann has at the beginning of the first day = $25.

At the end of the first day Ann had:

$\frac{2}{3} \ of\ 25$

$=\frac{2}{3} \times 25$

$=\$\frac{50}{3} .$

So, at the end of the first day Ann had $=\$\frac{50}{3} .$

Now, to get the money Ann have at the end of the second day:

$\frac{4}{7} \ of\ \frac{50}{3}$

$=\frac{4}{7} \times \frac{50}{3}$

$=\frac{200}{21}$

$=\$9\frac{11}{21} .$

Therefore, Ann have at the end of the second day $\$9\frac{11}{21}.$

8 0

3 years ago

adam and his dad share the cost of a meal in the ratio of 2:3. adam's dad pays £52.20. What is the total cost of the meal?

n200080 [17]

Adam's dad paid £52.20.
This is considered three "parts" of the total cost.
Let's divide by 3 to find the size of one part.
£52.20 ÷ 3 = £17.40
Now, multiply by 5 (Adam's parts + his dad's) to get the total cost.
$\boxed{\£87}$

8 0

3 years ago

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