Answer:
1.44 atm
Explanation:
Step 1:
We'll begin by calculating the number of mole in 2,800,000 Liter of air.
I mole of air occupy 22.4L.
Therefore, Xmol of air will occupy 2800000L i.e
Xmol of air = 2800000/22.4
Xmol of air = 125000 moles
Step 2:
Determination of the pressure when the balloon is fully inflated .
This can be obtained as follow:
Number of mole (n) of air = 125000 moles
Volume (V) = 2800000 L
Temperature (T) = 120°C = 120°C + 273 = 393K
Gas constant (R) = 0.082atm.L/Kmol
Pressure (P) =.?
PV = nRT
Divide both side V
P= nRT/V
P= (125000x0.082x393) / 2800000
P = 1.44 atm
Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm
Explanation:
please write full question
I think the answer would be A because O is oxygen and it has 7. Although it’s in parentheses and has a 2 on the outside of those parentheses, so you would multiply and 7 x 2 = 14. 14 is larger than the other ones.
Hopefully I’m right and hopefully that helps.
Answer:
The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want.
change 25 grams of potassium chlorate to moles.
calculate the gram molecular mass of potassium chlorate.
Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron.
1 K x 39 grams/mole
+1 Cl x 35.4 grams/ mole
+3 O x 16 grams/ mole
= 122.4 grams / mole Potassium Chlorate
25
122.4
= moles.
2.05 moles of Potassium Chlorate.
There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride.
2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride.
Find the gram molecular mass of Potassium Chloride.
1 K x 39 = 39
+1 Cl x 35.4 = 35.4
= 74.4 grams / mole.
2.05 moles x 74.4 grams/ mole = 15.2 grams
Explanation:
big brain ;)