Answer:
114.48g
Explanation:
Step 1:
Data obtained from the question:
Volume (V) = 162 L
Pressure (P) = 1.20 atm
Temperature = 100°C = 100°C+ 273 = 373K
Number of mole (n) of H2O =?
Recall:
Gas constant (R) = 0.082atm.L/Kmol
Step 2:
Determination of the number of mole of H2O i.e steam.
Using the ideal gas equation, the number of mole of H2O can be obtained as follow:
PV = nRT
1.2x 162 = n x 0.082 x 373
Divide both side by 0.082 x 373
n = (1.2x 162) /(0.082 x 373)
n = 6.36 moles
Step 3:
Determination of mass of H2O i.e steam:
This is illustrated below:
Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol
Number of mole H2O = 6.36 moles
Mass of H2O =?
Mass = number of mole x molar Mass
Mass of H2O = 6.36 x 18
Mass of H2O = 114.48g
Therefore, the mass of H2O i.e steam required to fill the drum of crude oil is 114.48g
