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grigory [225]
3 years ago
14

6/5-4/15 can you help me get the answer?

Mathematics
2 answers:
victus00 [196]3 years ago
5 0
14/15 should be the answer :) if you can find a way to simplify it I would and I’m sorry if I’m wrong
algol133 years ago
5 0
6/5 - 4/15
First let’s look at the denominator
We need to get both denominations to be the same number by using multiplication
Do you know how to do that
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Drawing a red marble from a bag of six red and 4 blue replacing it and then drawing a blue marble
Ksivusya [100]

Answer:

The probability of picking a red marble and a blue marble = 6/25

Step-by-step explanation:

Here, the question is INCOMPLETE.

What is the probability of this independent event. Drawing a red marble from a bag of 6 red and 4 blue marbles, replacing it, and then drawing a blue marble.

Here, total number of red marble in bag = 6

total number of blue marble in bag = 4

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Now,if E : Any given event, then

\textrm{P (Event E)} = \frac{\textrm{Total number of favorable outcomes}}{\textrm{Total Outcomes}}

So, here \textrm{P (Picking a Red marble)} = \frac{\textrm{Total number of red marble}}{\textrm{Total marble}} = \frac{6}{10}  = \frac{3}{5}

⇒ P(a Red ball)  = 3/5    ...... (1)

Now, if the picked marble is REPLACED, then total marbles in the bag  = 10

So, here \textrm{P (a Blue marble)} = \frac{\textrm{Total number of blue marble}}{\textrm{Total marble}} = \frac{4}{10}  = \frac{2}{5}

⇒ P(a Blue marble)  = 2/5    ...... (2)

So, the probability of picking a red marble and a blue marble AFTER REPLACING

=P(a Red marble) x P(a Blue marble)  = 3/5 x 2/5  = 6 /25

Hence, the probability of picking a red marble and a blue marble = 6/25

7 0
4 years ago
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4 years ago
Identify the natural number that is closest to 14‾‾‾√.<br><br> A 4<br> B 14<br> C 5<br> D 3
WINSTONCH [101]

Answer:

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Step-by-step explanation:

\sqrt{14}= 3.74165738677

≈4

the number 7 before de "."  being greater than 5 rounds up to the next number, in this case 4

8 0
3 years ago
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