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3 years ago

While on vacation in Colorado, an extended

1 answer:

7 0

Answer: The equation for a straight line is a linear equation. Since linear usually stands for anything straight or in a line, thus the equation for lines in the XY plane is referred to be a linear equation. For example, 2x+3y = 5 is a linear equation in two variables.

Step-by-step explanation:

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Andre took 6 kicks and made 4 goals: 4/6

Harman [31]

I believe it’s 16/24 and 20/30

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2 years ago

Pls help will give barainliest

BARSIC [14]

Answer:

i dont know

Step-by-step explanation:

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3 years ago

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PLEASE HELP ASAP!! WILL MARK BRAINLIEST

KATRIN_1 [288]

The slope is mx+b so find two points in the graph and use y-rise/x-run

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4 years ago

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F(x, y, z) = z tan−1(y2)i + z3 ln(x2 + 3)j + zk. find the flux of f across s, the part of the paraboloid x2 + y2 + z = 18 that l

Cerrena [4.2K]

$\mathbf F(x,y,z)=z\tan^{-1}(y^2)\,\mathbf i+z^3\ln(x^2+3)\,\mathbf j+z\,\mathbf k$
$\implies\mathrm{div}\mathbf F(x,y,z)=0+0+1=1$

By the divergence theorem, the flux of $\mathbf F$ across the *closed* surface $\mathcal S$ combined with the plane $z=2$ is given by a volume integral over the closed region:

$\displaystyle\iint_{\mathcal S}\mathbf F\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf F\,\mathrm dV$

So in fact, to find the flux over $\mathcal S$ alone, we'll need to subtract the flux of $\mathbf F$ over the planar portion, oriented outward. First, compute the volume integral by converting to cylindrical coordinates:

$x^2+y^2+z=18$
$z=2\implies x^2+y^2=16\implies r^2=16\implies r=4$

$\displaystyle\iiint_{\mathcal R}\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}\int_{z=2}^{z=18-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=128\pi$

If the surface does actually contain $z=2$ , then you can stop here; otherwise, continue.

Now, parameterize the part of the *closed* surface in $z=2$ by

$\mathbf s(r,\theta)=r\cos\theta\,\mathbf i+r\sin\theta\,\mathbf j+2\,\mathbf k$

where $0\le r\le4$ and $0\le\theta\le2\pi$ . We get a surface element

$\mathrm d\mathbf S=(\mathbf s_r\times\mathbf s_\theta)\,\mathrm dr\,\mathrm d\theta=(r\,\mathbf k)\,\mathrm dr\,\mathrm d\theta$

We don't need to worry about the first two components of

and so the surface integral over this region is

$\displaystyle\iint_{z=2\,\land\,x^2+y^2\le16}\mathbf F\cdot\mathrm d\mathbf S=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}2r\,\mathrm dr\,\mathrm d\theta=32\pi$

Then the total flux over $\mathcal S$ alone is $(128-32)\pi=96\pi$ .

4 0

3 years ago

Marissa and Callie both have babysitting jobs. Marissa charges $19 plus $1.50 per hour. Callie charges $15 plus $2.75 per hour.

aliya0001 [1]

Answer:

4 hours

Step-by-step explanation:

Write an equation

19 +1.5x < 15+2.75x

Subtarct 15 on both sides

4+1.5x<2.75x

subtract 1.5x on both sides

4< 1.25x

Divide 1.25 on each side

3.2<X

Since they on,y charge per hour so 4 hours

3 0

4 years ago

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