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slega [8]
3 years ago
15

Which equations have no real solution but have two complex solutions?

Mathematics
2 answers:
Sidana [21]3 years ago
6 0

Answer:

Since we cannot find the square root of a negative number (at least not using the real number system), we cannot evaluate the formula any further. There will be no solutions. Use the discriminant to determine whether the quadratic equation has two, one, or no solutions. The result is a negative number. i really hope this helps u. good luck my dude



Sphinxa [80]3 years ago
5 0

Answer:

equations have no real solution but have two complex solutions When  discriminant is negative.

Step-by-step explanation:

The quadratic equation ha 2 solution

let a, b and c are the coefficients of equation.

These 2 solutions are based on the value of discriminant,

<u>discriminant = square root (b^2 - 4ac) </u>

If b^2 - 4ac  is a negative value we cannot find its root.

The square root of a negative number is complex number.

Therefore equations have no real solution but have two complex solutions

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4x-5=x-1+3x I need help
labwork [276]

Answer:

x = no solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

4x - 5 = x - 1 + 3x

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                    4x - 5 = 4x - 1
  2. Subtract 4x on both sides:          -5 ≠ -1

Here we see that -5 does not equal -1.

∴ This equation has no solutions.

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Marrrta [24]

Answer:

leading coefficient is 18

and the degree is also 18

Step-by-step explanation:

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