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3 years ago

Which equations have no real solution but have two complex solutions?

Mathematics

2 answers:

Sidana [21]3 years ago

6 0

Answer:

Since we cannot find the square root of a negative number (at least not using the real number system), we cannot evaluate the formula any further. There will be no solutions. Use the discriminant to determine whether the quadratic equation has two, one, or no solutions. The result is a negative number. i really hope this helps u. good luck my dude

Sphinxa [80]3 years ago

5 0

Answer:

equations have no real solution but have two complex solutions When discriminant is negative.

Step-by-step explanation:

The quadratic equation ha 2 solution

let a, b and c are the coefficients of equation.

These 2 solutions are based on the value of discriminant,

<u>discriminant = square root (b^2 - 4ac) </u>

If b^2 - 4ac is a negative value we cannot find its root.

The square root of a negative number is complex number.

Therefore equations have no real solution but have two complex solutions

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$\qquad\qquad\huge\underline{{\sf Answer}}$

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