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slega [8]
4 years ago
15

Which equations have no real solution but have two complex solutions?

Mathematics
2 answers:
Sidana [21]4 years ago
6 0

Answer:

Since we cannot find the square root of a negative number (at least not using the real number system), we cannot evaluate the formula any further. There will be no solutions. Use the discriminant to determine whether the quadratic equation has two, one, or no solutions. The result is a negative number. i really hope this helps u. good luck my dude



Sphinxa [80]4 years ago
5 0

Answer:

equations have no real solution but have two complex solutions When  discriminant is negative.

Step-by-step explanation:

The quadratic equation ha 2 solution

let a, b and c are the coefficients of equation.

These 2 solutions are based on the value of discriminant,

<u>discriminant = square root (b^2 - 4ac) </u>

If b^2 - 4ac  is a negative value we cannot find its root.

The square root of a negative number is complex number.

Therefore equations have no real solution but have two complex solutions

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Simplify to create an equivalent expression "-4(-11+4n)-3(-2n+9)"
ad-work [718]

The expression -4 (-11 + 4n) – 3(- 2n + 9) is equivalent to the expression 17 — 10n.

<h3>What is an equivalent expression?</h3>

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

⇒ -4 (-11 + 4n) – 3(- 2n + 9)

On simplifying, we have

⇒ 44 – 16n + 6n – 27

⇒ 17 — 10n

More about the equivalent link is given below.

brainly.com/question/889935

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2 years ago
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4 years ago
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if a 14 foot tree casts a 8 foot long shadow. how tall is a tree that casts a 4 foot long shadow?
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Given:

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Using proportion;

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What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction?
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Step-by-step explanation:

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B) 50%

4/8 (the fraction of the slices eaten)

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1/2 or 50%

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