a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant. Given that a(2) = 0, what is the absol

Question

2 years ago

15

ute value of the product of the zeros of a?

2 answers:

morpeh [17] · Answer 1 · 2022-07-17T08:05:34+03:00

7 0

Zeros:
t-k=0, t=k
t-3=0, t=3
t-6=0, t=6
t+3=0, t=-3
abs value of the product= abs value of (t*3*6*-3)=54t

koban [17] · Answer 2 · 2022-07-17T05:39:37+03:00

koban [17]2 years ago

4 0

If a(2) = 0, then k=2. The product of the zeros is
(2)*(3)*(6)*(-3) = -108

The absolute value of the product of zeros of a(t) is 108.