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Oduvanchick [21]
3 years ago
13

IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. Using the empirical rule, what percentage

of people have an IQ score between 70 and 130?​
Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

70 = 100 - 2•15 is 2 s.d.'s below the mean.

130 = 100 + 2•15 is 2 s.d.'s above the mean.

By the empirical rule,

Pr [70 ≤ X ≤ 130] = Pr [-2 ≤ Z ≤ 2] ≈ 95%

(where Z is normally distributed with mean 0 and s.d. 1)

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irga5000 [103]

Answer:

1 & 2 perpudicular

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Step-by-step explanation:

7 0
3 years ago
The times for completing one circuit of a bicycle course are normally distributed with
Sonja [21]

Answer:

The answer is 76.9 rounded or rounds.

Step-by-step explanation:

Solution

Given that:

Mean = μ = 72.5

Standard deviation = σ = 6.5

Now

By applying the standard normal table we have the following:

P(Z < z) = 75%

= P(Z < z)

= 0.75

Thus

z =0.67 by using the standard normal z table

Applying the  z-score formula we have:

x = z * σ + μ

x = 0.67*6.5+72.5

x= 76.855 ≈ 76.9

Therefore the cutoff time is 76.9 rounds.

4 0
3 years ago
Alternate interior angles are always congruent. TRUE OR FALSE
Fudgin [204]

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false

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7 0
3 years ago
Read 2 more answers
Type your answer in the box.<br>Evaluate y3 – 2y (y – 5) + 13 when y = -3​
kap26 [50]

Answer:

-62

Step-by-step explanation:

y³ – 2y (y – 5) + 13

when y = -3

y³ – 2y (y – 5) + 13

=(-3)³ – 2(-3) [ (-3) – 5] + 13  (by PEDMAS, evaluate parentheses first)

=(-27) + (6) (-8) + 13   (next do multiplication)

=(-27) + (-48) + 13

= -27 - 48 + 13

= -62

3 0
3 years ago
Maids, Inc. offers a maid service whose fees are defined by the function C(t) below, where t represents the number of hours purc
Anna [14]

Given:

The cost function C(t) = 45t + 95 where t is the number of hours purchased

To Find:

The amount of money a customer pays more for using the service for 5 hours than for 3 hours

Solution:

A customer has to pay $90 more to use the service for 5 hours than for 3 hours.

Calculation:

First, we find the cost of using the service for 3 hours, i.e., at t=3. We do this by substituting t=3 in the cost function C(t) = 45t + 95

C(t) = 45(3) + 95 = 230

Thus the cost for using the service for 3 hours is $230.

Next, we find the cost of using the service for 5 hours, i.e., at t=5. We do this by substituting t=5 in the cost function C(t) = 45t + 95

C(t) = 45(5) + 95 = 320

Thus the cost for using the service for 5 hours is $320.

The difference in the two prices is $(320-230) = $90

So, a customer has to pay $90 more to use the service for 5 hours than for 3 hours.

3 0
4 years ago
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