Prove that x+1 is a factor of x^n+1 where n is an odd positive integer.
1 answer:
Answer:
because x^n+1 =
the number which is n and n is an odd number and my odd number is 3 so
x^3+1= 4
= x^4
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divide 2 b 3
2 divided by 3 = 0.625
move decimal point 2 places to the right to turn to a percentage
0.625 = 62.5%
Answer:
the answer is d ur welcome.
8 ÷ (7 - 9) * ( 4 + (-4) ) <--- notice that bolded part.
4 + (-4) = 4 - 4 = 0.
after that, you're pretty much dividing and multiplying by 0, so
whatever ÷ whatever * whatever * 0 = 0.
Answer:
4
Order of Operations is what you have to use
Answer:
I thinks it’s 7x + 5
Step-by-step explanation:
