All categories

3 years ago

Solve this please 6x = 1,620

Mathematics

2 answers:

mylen [45]3 years ago

8 0

6 x 270= 1,620
I hope this helped

REY [17]3 years ago

5 0

Ok, just think about it like division. Divide 1620 by 6 and that will leave you with x=270

You might be interested in

Which graph shows the line of best fit for the data

lys-0071 [83]

Answer:

Graph C shows the line of best fit for the data.

Step-by-step explanation:

The line of Graph C is more centered and even than the other ones

4 0

2 years ago

Find the volume of the pyramid.

Anon25 [30]

V=7 with the little 3

6 0

2 years ago

500(x – 3) = 5,000<br><br> What’s the value of x?

Vladimir79 [104]

Answer:

Step-by-step explanation:

500(x-3)=5000

500x-1500=5000

500x=5000+1500

500x=6500 /:500

x=13

4 0

3 years ago

Read 2 more answers

Gerard has $30 to spend on lunches this month. Lunch costs him $1.50 each day. After Gerard buys lunch for 8 days, which stateme

Harrizon [31]

What i did is that i did $1.50 time 8 = $12.00 and then do $30.00-12.00=$18.00

6 0

2 years ago

Read 2 more answers

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers