An object traveling with an initial constant speed along the y-axis begins to decelerate 4 kilometers before reaching a referenc
e position. Its position is given by the function y
=
−
t
2
+
3
t
−
4
, where t is the time in seconds. Which value is equal to the average rate of change of the function over the interval
(
0
,
−
4
)
to
(
2
,
−
2
)
?
The value that is equal to the average rate of change of the function over the interval is equal is 1 m/s
<h3>The average rate of change</h3>
Given the position of the object expressed as:
y = -t^2 + 3t - 4
In order to calculate the value that is equal to the average rate of change of the function over the interval (0, -4) and (2, -2), we will determine the slope of these two coordinates as shown;
Rate of change = -2-(-4)/2-0 Rate of change = -2+4/2 Rate of change = 2/2
Rate of change = 1 m/s
Hence the value that is equal to the average rate of change of the function over the interval is equal is 1 m/s
