Answer:
80%
Explanation:
The thermal energy output by the oven is 800 J which is the useful energy that can be utilized for cooking.
The electrical energy input to the oven is 1000 J.
The efficiency of the oven =
(Useful energy output)/(Total energy input to the oven) x 100

Hence, the efficiency of the oven is 80%.
Answer:
16 Newtons
Explanation:
We will use the equation F=ma
First, find the acceleration using the givens.
a=∆v/∆t
a=15-3/3
a=12/3
a=4 m/s^2
Next, plug the acceleration and mass into the equation.
F=ma
F=4kg(4m/s^2)
F=16 Newtons
The radius of a helium atom 4.8 times bigger then the radius of an alpha particle.
<h3>What is
alpha particle?</h3>
The structure of alpha particles, also known as alpha rays and alpha radiation, is similar to that of the helium-4 nucleus and has been made up of two protons as well as two neutrons bonded together.
<h3>What is
helium?</h3>
For welding metals like aluminum, helium was utilized as an inert gas environment. It is also employed in rocket propulsion.
The radius of a helium atom 4.8 times bigger then the radius of an alpha particle. More precisely than it's ever been, the diameter of the helium atom's nucleus, the alpha particle, had also been measured. Outcomes just point to a size of 1.6782 femtometers, 4.8 times more accurate than earlier readings.
To know more about helium and alpha particle.
brainly.com/question/2288334
#SPJ3
The speed of light : 299 792 458 m / s
MARK ME BRAINLIEST PLEASE!!!!!
The total energy TE = mgh + 1/2 mU^2; where h = 20 m, g = 9.81 m/sec^2, and U = 10 mps. When the ball reaches max height H, all that TE will be potential energy PE = mgH = TE.
So there you are. TE = mgh + 1/2 mU^2 = mgH = TE from the conservation of energy. Solve for H.
1) H = (gh + 1/2 U^2)/g = h + U^2/2g = ? meters where everything on the RHS is given. You can do the math.
2) As the ball drops from H to h, it picks up KE as the potential energy mgH is converted when the potential energy is diminished to mgh, where h < H. So PE - pe = ke = mg(H - h) = 1/2 mv^2 so solve for v = sqrt(2g(H - h)) and, again, everything is given. You can do the math.
3) Same deal as 2) except now its V = sqrt(2gH) because all the PE = mgH = 1/2 mV^2 = KE when it is about to hit the ground. You can do the math.