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Roman55 [17]
3 years ago
13

What is the speed of light?

Physics
2 answers:
Sergeu [11.5K]3 years ago
5 0
The speed of light : 299 792 458 m / s
Katarina [22]3 years ago
5 0
<em>speed of light is constant and its value is <u>299,792,458 m/s...
</u>also it is <u>299,792 in km per second... :)</u><u>
</u></em>
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If the axes of the two cylinders are parallel, but displaced from each other by a distance d, determine the resulting electric f
Novay_Z [31]

Answer:

E =  ρ ( R1²) / 2 ∈o R

Explanation:

Given data

two cylinders are parallel

distance = d

radial distance = R

d < (R2−R1)

to find out

Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants

solution

we have two parallel cylinders

so area is 2 \pi R × l

and we apply here gauss law that is

EA = Q(enclosed) / ∈o   ......1

so first we find  Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( \pi R1² × l )

so put all value in equation 1

we get

EA = Q(enclosed) / ∈o

E(2 \pi R × l)  = ρ ( \pi R1² × l ) / ∈o

so

E =  ρ ( R1²) / 2 ∈o R

6 0
3 years ago
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

3 0
3 years ago
An amusement park ride moves a rider at a constant speed of 14 meters per second in a horizontal circular path of radius 10. met
ASHA 777 [7]

Answer:

B) 2g

Explanation:

<u>Given the following data;</u>

Velocity, v = 14m/s

Radius, r = 10m

To find the centripetal acceleration;

Acceleration, a = \frac {v^{2}}{r}

Substituting into the equation, we have;

Acceleration, a = \frac {14^{2}}{10}

Acceleration, a = \frac {196}{10}

Acceleration, a = 19.6m/s²

In terms of acceleration due to gravity, g = 9.8m/s²

We would divide by g;

Acceleration, a = 19.6/9.8 = 2

Hence, centripetal acceleration = 2g

Therefore, the rider's centripetal acceleration in terms of g, the acceleration due to gravity is 2g.

4 0
3 years ago
As a 5.0 x 102 N basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on the floo
s2008m [1.1K]
Here is your answer:

First find the notations:

5.0×10^2=500.
1.0×10^3=1,000

Then you multiply:

1,000×500=500,000

Your answer is...
=500,000 or 5.0×10^4
8 0
4 years ago
Can someone help me this question ​
vladimir2022 [97]

Answer:

Volume of wood is 68-50 = 18 cm³

Explanation:

<h2>Hope it helps you</h2>
4 0
3 years ago
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