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2 years ago

What is the speed of light?

Physics

2 answers:

Sergeu [11.5K]2 years ago

5 0

The speed of light : 299 792 458 m / s

Katarina [22]2 years ago

5 0

speed of light is constant and its value is 299,792,458 m/s...
also it is 299,792 in km per second... :)

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Air enters a turbine operating at steady state with a pressure of 75 Ibf/in.^2, a temperature of 800º R and velocity of 400 ft/s

Arturiano [62]

Answer:

(a) W/m = 49.334 Btu/lb

(b) $\frac{E_{d} }{m}$ = 22.12 Btu/lb

Explanation:

For the given problem, it can be assumed that the system is operating at steady state and the effects of potential energy can be neglected.

(a) Using the thermodynamic table for air.

At the temperature ( $T_{1}$ )of 800 ºR and pressure ( $P_{1}$ ) of 75 Ibf/in.^2, we can deduce that:

Specific enthalpy ( $h_{1}$ ) = 191.81 BTu/lb

Specific entropy ( $s_{1}$ ) = 0.6956 Btu/(lb.ºR)

At the temperature ( $T_{2}$ )of 600 ºR and pressure ( $P_{2}$ ) of 15 Ibf/in.^2, we can deduce that:

Specific enthalpy ( $h_{2}$ ) = 143.47 BTu/lb

Specific entropy ( $s_{2}$ ) = 0.6261 Btu/(lb.ºR)

The work done can be calculated using energy rate equation:

$\frac{W}{m} = \frac{Q}{m} + (h_{1} - h_{2}) + \frac{V_{1}^{2} - V_{2}^{2}}{2}$

Q/m = heat transfer = -2 Btu/lb

$V_{1}$ = 400 ft/s

$V_{2}$ = 100 ft/s

$\frac{W}{m} = -2 + (191.81 - 143.47) + \frac{400^{2} - 100^{2}}{2}*[tex]\frac{1}{2*32.2*778}$ [/tex] = -2 + 48.34 + 29.938 = 49.334 Btu/lb

(b) To calculate the exergy destruction, we will use the equation for exergy rate:

$\frac{E_{d} }{m} = [1-\frac{T_{o} }{T_{b} }](\frac{Q}{m}) - \frac{W}{m} + [(h_{1} - h_{2}) -T_{o}(s_{1} - s_{2}) + \frac{V^{2} _{1} - V_{2} ^{2}}{2}]$

The equation above is further simplified to:

$\frac{Ed}{m} = T_{o}[(s_{2} -s_{1}) - Rln\frac{P_{2} }{P_{1} } - \frac{Q/m}{T_{b} }]$

Using a reference temperature (To) = 500 °R

Average surface temperature (Tb = 620°R

$\frac{Ed}{m} = 500*[(0.6261 -0.6956) - (1.986/28.97)ln\frac{15 }{75 } - \frac{-2}{620}}]$

$\frac{E_{d} }{m}$ = 500*[-0.0695 +0.068688*1.609 +0.003225] = 22.12 Btu/lb

5 0

3 years ago

Sinisimulan ko Kaya Ko Gagawin ko Nalaman ko Natututo Ako

ozzi

Answer:

what!!!!!!

Explanation:

didn't got the point

7 0

2 years ago

A cylindrical shell of radius 7.00 cm and length 2.21 m has its charge uniformly distributed on its curved surface. The magnitud

polet [3.4K]

Answer:

The net charge on the shell is 30x10^-9C

Explanation:

Pls see attached file

8 0

3 years ago

Three identical metallic conducting spheres carry the following charges: q = +3.8 μC, q = −2.6 μC, and q = −8.8 μC. The spheres

Kitty [74]

Answer:

-4.1μC is the final charge on the third sphere

Explanation:

From the given data, q1 and q2 are brought into contact as they are both conductors, as such there will be evenly distribution of charges.

a) charge on each sphere(Q) = q1 + q2 / 2

= +3.8 μC + (- 2.6 μC) / 2 = 1.2μC/2 = 0.6μC

b) Now, one of those two spheres is brought into contact with the third sphere ; Q is brought into contact with q3 = Q + q3 / 2

= 0.6μC - 8.8 μC /2 = -8.2 μC/2

= -4.1μC is the final charge on the third sphere.

6 0

3 years ago

State and explain the principle of superposition of electrostatic force

ella [17]

Answer:

The principle of superposition states that when a number of charges are interacting, the net electrostatic force a given charge is the vector sum of the forces exerted on it due to all other charges. The force between two charges is not affected by the presence of other charges.

8 0

2 years ago