Answer:
For an object to accelerate, appropriate force must be applied to the object to cause it to change it’s velocity if it’s already in motion. However, to cause it to overcome static friction if it is at rest, and cause it to change it’s velocity
Explanation:
Answer:
Incomplete question
Complete question:
a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 44kg , the acceleration of the object is 4m/s². If the same force acts upon another object whose mass is 11kg what is this object's acceleration?
Answer: 8m/s²
Explanation:
From the statement we deduced that acceleration varies inversely with mass where force was kept constant.
Therefore,
F/m = a or F = ma
For the first statement, substituting the mass and acceleration gives:
F = 44 x 4 = 88N
Applying the force above to the second mass gives us:
a = 88/11 = 8m/s²
<span>gravitational force = 0.1 mg-wt. = 0.1 * 10^-6 * 9.8 N = Gm1m2/r^2
m1 = 40 kg m2 =15 kg and r = 0.2 m
Put in and find G</span>
Answer:
10 m/s
Explanation:
Given:
Amplitude of atomic vibrations (λ) = 10⁻⁹ cm = 10⁻⁹ × 10⁻² m = 10⁻¹¹ m [1 cm = 10⁻² m]
Frequency of the vibrations (f) = 10¹² Hz
In order to find the atom's maximum speed, we need to make use of the formula that relates speed, frequency and wavelength of the vibration.
Therefore, the formula for maximum speed is given as:
Now, plug in the values given and solve for speed 'v'. This gives,
Therefore, the atom's maximum speed due to thermal energy provided is 10 m/s.
Answer:
2 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Final velocity (v) = 12 m/s
Time (t) = 6 s
Acceleration (a) =?
The acceleration of the player can be obtained as follow:
v = u + at
12 = 0 + (a × 6)
12 = 6a
Divide both side by 6
a = 12 / 6
a = 2 m/s²
Thus, the acceleration of the player is 2 m/s²
