Work = Force x displacement
Force= 20N
Displacement= 0.75m
W= 20(0.75)
W= 15 Nm
Answer:
8 x 10^-8 C on both the spheres.
Explanation:
Number of electrons added to A = 1 x 10^12
As the sphere A and B are identical to each other so the charge is shared equally.
Charge of one electron = 1.6 x 10^-19 C
Charge on A after wards
= number of electrons after wards x charge of one electron
qA = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C
Similarly, the charge on sphere B afterwards
= number of electrons after wards x charge of one electron
qB = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C
Answer: a) 10.4km
b) 0.62h
C) 17km/h
d) 9.1km/h
Explanation:
A) suppose you move in the positive direction of an x axis, from a first position of x1 = 0 to a second position of x2 at the station. That second position must be at x2 = 8.4 km + 2.0 km = 10.4 km.
B) time interval Dtwlk (= 0.50 h), but we don't know the driving time interval Dt/dr. However, we know that for the drive the displacement Dx/dr is 8.4 km and the average velocity vavg,dr is 70 km/h.
This average velocity is the ratio of the displacement for the drive to the time interval for the drive:
dv = dx/ dt
dt = dx/dv = 8.4/70 = 0.12h
t = ti + two
t = 0.12 + 0.50 = 0.62h
C) avg speed for the entire trip is the ratio of the displacement of 10.4 km for the entire trip to the time interval of 0.62 h for the entire trip.
Avg v = distance/time
10.4/0.62 = 16.8km/h
D) average speed is the ratio of the total distance you move to the total time interval you take to make that move. The total distance is 8.4 km + 2.0 km + 2.0 km = 12.4 km. The total time interval is 0.12 h + 0.50 h + 0.75 h = 1.37 h.
Avg speed = 12.4/1.37 = 9.1km/h
