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2 years ago

Type the correct answer in the box. Use numerals instead of words.

Mathematics

1 answer:

Mashutka [201]2 years ago

4 0

About 115°

Step-by-step explanation:

By 2 pi r, total circumference is about 942
Length of an arc = 2 pi r (theta/360)
We needed to find theta(angle) here
Easily putting all the values gives us 115°

$\huge\bold{\purple{\bold{⚡Easy,right? ⚡}}}$

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Rose spent 124 on 10 cars & 4 cats what is the cost for 1 car & 1 cat.

Rudiy27

Answer:

$6 per cat, $10 per car

Step-by-step explanation:

I guess and checked my work.

4 0

3 years ago

Which expression is equivalent to square root 55x^7y6/11x^11y^8

Novay_Z [31]

Answer:

$\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}$

Step-by-step explanation:

$\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a$

$=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}$

6 0

3 years ago

40 POINTS NEED HELP ASAP

sesenic [268]

Use slope formula: y2-y1/x2-x1

XZ: -5/9
YZ: 2/7
XY: -7/2

XYZ is a right triangle because two of these slopes have a product of -1.

(YZ and XY does). We are all busy these days.

7 0

3 years ago

Read 2 more answers

Find the domain and range of f(x)= (2x+6) / ((x^2)-x-12)

creativ13 [48]

Answer:

Step-by-step explanation:

If you want to determine the domain and range of this analytically, you first need to factor the numerator and denominator to see if there is a common factor that can be reduced away. If there is, this affects the domain. The domain are the values in the denominator that the function covers as far as the x-values go. If we factor both the numerator and denominator, we get this:

$f(x)=\frac{2(x+3)}{(x-4)(x+3)}$

Since there is a common factor in the numerator and the denominator, (x + 3), we can reduce those away. That type of discontinuity is called a removeable discontinuity and creates a hole in the graph at that value of x. The other factor, (x - 4), does not cancel out. This is called a vertical asymptote and affects the domain of the function. Since the denominator of a rational function (or any fraction, for that matter!) can't EVER equal 0, we see that the denominator of this function goes to 0 where x = 4. That means that the function has to split at that x-value. It comes in from the left, from negative infinity and goes down to negative infinity at x = 4. Then the graph picks up again to the right of x = 4 and comes from positive infinity and goes to positive infinity. The domain is:

(-∞, 4) U (4, ∞)

The range is (-∞, ∞)

If you're having trouble following the wording, refer to the graph of the function on your calculator and it should become apparent.

8 0

3 years ago

What is the product of the two factors? (X 4/3) (X 2/3)

SpyIntel [72]

Answer:

$\frac{8}{9}{x}^{2}$

Step-by-step explanation:

All you do is multiply straight across [both denominator and numerator] to arrive at your answer. Then, multiplying two x's together gives you ${x}^{2}$ . So, with all that being said, you have your answer.

I am joyous to assist you anytime.

5 0

4 years ago

Read 2 more answers