Eliminate the bolded term y-10=30
2 answers:
Answer:
y = 40
Step-by-step explanation:
y-10=30
y=30+10
y=40
Answer:
Y-10=30
Y=30+10
Y=40
Step-by-step explanation:
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Answer:
A≈149.84
Step-by-step explanation:
A=a2+2aa2
4+h2=62+2·6·62
4+92≈149.842
Use pythagorean therom, so A^2 would be 12 since it’s the same lengths the square sides, and C^2 is 20. X= 16
The answer is 8.333333 it goes on and 3 is repeating.
1) to this case you must match both equations
3x+2 = 2x-3 ⇒3x-2x = -3-2⇒x= -5
now the value of x substitute it in the any of two equations, y = 3(-5)+2 = -13
and the other equation is the same value
y = 2(-5)-3 = -13
the point is ( -5,-13)
Answer:
<h3>Given</h3>
- m∠REG = 78°
- mAR = 46°
- ER ≅ GA
<h3>Solution</h3>
- m∠GAR = 180° - m∠REG = 180° - 78° = 102° (supplementary angles sum to 180°)
- m∠TAR = 1/2mAR = 1/2(46°) = 23° (tangent chord angle is half the size of intercepted arc)
- m∠GAN = 180° - (m∠TAR + m∠GAR) = 180° - (23° + 102°) = 55° (straight angle is 180°)
- mAG = 2m∠GAN = 2(55°) = 110°
- mRE = mAG = 110° (as ER ≅ GA)
- mGE = 360° - (mAG + mAR + mRE) = 360° - (110° + 46° + 110°) = 94° (full circle is 360°)
