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n200080 [17]
3 years ago
10

I need help can you help me?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0

D - -x^2 + 3x + 7

To find this, first write out the equation:

(3x + 1) - (x^2 - 6)

Distribute the negative into x^2 and -6 so you're equation now looks like this:

3 x + 1 - x^2 + 6

Combine like terms and arrange the equation into ax^2 + bx + c to get the final answer of:

-x^2 + 3x + 7

Hope this helps!

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16.00 dollars

Step-by-step explanation:

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what are the ex and Y coordinates of point E, which partition the directed line segment from A to B into a ratio of 1:2?
Paul [167]

Answer:

Step-by-step explanation:

The formula for this is the one we use when we are given the ratio the directed line segment is separated into as opposed to the point being, say, one-third of the way from one point to another. The 2 equations we use to find the x and y coordinates of this separating point are:

x=\frac{bx_1+ax_2}{a+b}  and  y=\frac{by_1+ay_2}{a+b} where x1, x2, y1, y2 come from the coordinates of A and B, and a = 1 (from the ratio) and b = 2 (from the ratio). Filling in for x first:

x=\frac{2(2)+1(-4)}{1+2}=\frac{4-4}{3}=0 and then y:

y=\frac{2(-3)+1(9)}{1+2}=\frac{-6+9}{3}=\frac{3}{3}=1

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2 years ago
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If 2y=x³ + 2x², find dy/dx when x=2.
scZoUnD [109]

Answer:

10

Step-by-step explanation:

\boxed{\textsf{If }y=x^n,\: \textsf{then }\dfrac{\text{d}y}{\text{d}x}=nx^{n-1}}

<u>Given equation</u>:

2y=x^3+2x^2

Isolate y by dividing both sides by 2:

\implies y=\dfrac{1}{2}x^3+x^2

Differentiate with respect to x:

\implies \dfrac{\text{d}y}{\text{d}x}=3 \cdot \dfrac{1}{2}x^{3-1}+2 \cdot x^{2-1}

\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{3}{2}x^2+2x

Finally, substitute x = 2 into the differentiated equation:

\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =\dfrac{3}{2}(2)^2+2(2)\\\\ & = \dfrac{3}{2}(4)+4\\\\ & = \dfrac{12}{2}+4\\\\ & = 6+4\\\\ & = 10\end{aligned}

Learn more about differentiation here:

brainly.com/question/27958412

brainly.com/question/26488862

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