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S_A_V [24]
3 years ago
11

20 - (-3) + 15 help a girl outt :(

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0

Answer:

38

Step-by-step explanation:

20-(-3+)15=38

Kryger [21]3 years ago
6 0

Answer is 38

20 -(-3) + 15

20 + 3 + 15

38

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−\frac{7}{10} ÷\frac{2}{5}
bazaltina [42]
$$ −\frac{7}{10} \div\frac{2}{5}= \frac{-7}{4} $$ . totally answer. I hope helping with this answer
3 0
3 years ago
Find:
JulijaS [17]

Answer:

a) 15 ÷ 2/3=

=1 5 x 3/2=45/2

b) 3 × 1/8 × 6/9

=1/8 x 2(  Simplify 3 with 9 remainder 3, reduce

6 with 3 remainder 2)

=1/4

c) 3 3/5 ÷ 2 2/5

=18/5 : 12/5

=18/5 . 5/12

=3/2

d) 2 1/12 × 1 1/5

= 25/12 . 6/5

=5/2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Here is a triangle with the height on the side of the triangle. Use the formula: (1/2)*(Base)*(Height) to find the area of the t
jasenka [17]

<em>(If one square on the graph = one centimeter)</em>

<u>b = 10cm</u>

<u>b = 10cmh = 10cm</u>

Area:

=  \frac{1}{2}  \times b \times \: h

=  \frac{1}{2 }  \times 10 \times 10

=  \frac{1}{2}  \times 100

= 50 {cm}^{2}

3 0
3 years ago
The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
3 years ago
A water balloon is 5 feet above the ground when Sally launches it into the air. Use the quadratic equation 0 = -t2 + 4t + 5 to f
Alborosie

Answer:

2-sqrt14/2, 2+sqrt13/2.

Step-by-step explanation:

What you do is you have to do the quadratic equation like it says in the problem.

x=  −b± sqrtb^2 −4ac /2a .

a=-2, b=4, c=5.

x=-4±sqrt(4)^2-4(-2)(5)/2(-2).

x=-4±sqrt16+40/-4.

x=-4±2sqrt14/-2.

2-sqrt14/2, 2+sqrt13/2. is your answer once you have done everything.

​  

​

6 0
3 years ago
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