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Flauer [41]
3 years ago
15

3y+7<2-y help doing a test rn please help fast

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

y<-5/4

Step-by-step explanation:

3y+7<2-y

-7 on both sides

3y<-5-y

+y on both sides

4y<-5

divide by 4 on both sides

y<-5/4

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Jon and Becky measured the circle-shaped part of a sun they drew on the sidewalk.
PIT_PIT [208]

Answer:  The approximate area of the circle is:  <span>3,629.84 cm² .</span>
______________________________________________________
Area of a circle, "A" :  A = π * r² ;

  in which: A = Area of circle ;
               π <span>≈ 3.14 ; 
</span>               r = radius; 

radius of a circle, "r" = d / 2  ;  in which:  "d = diameter" ;

Given "d = 64 cm " ; 
         
                       r = d / 2 = 64 cm / 2 = 32 cm ;
____________________________________________
   So;    A = π * r²  ;
 
            A ≈ (3.14) * (32 cm)² ;
 
            A ≈ (3.14) * (1156 cm²) ;
_____________________________________________

            A  ≈  3,629 .84 cm²  .
_____________________________________________
3 0
3 years ago
Classify the following polynomials by the number of terms and degrees<br> -2x^3 +5x
cestrela7 [59]

Answer:

A third degree binomial

Step-by-step explanation:

The highest power is 3 hence the 3rd degree

and there are 2 terms hence the bi-nomial

8 0
3 years ago
The angle of elevation from a buoy in the water to the top of a lighthouse is 68degrees. If a buoy is 300 ft from the base of th
Katen [24]

Answer:

The height of the lighthouse is 742.5\ ft

Step-by-step explanation:

Let

h -----> the height of the lighthouse

we know that

The tangent of angle of 68 degrees is equal to divide the height of the lighthouse by the horizontal distance from the buoy to the base of lighthouse

so

tan(68\°)=\frac{h}{300}

Solve for h

h=(300)tan(68\°)=742.5\ ft

7 0
3 years ago
The product of 3! is
Alex17521 [72]

Answer:15 is the answer. Product is what you get when you multiply two or more numbers together. In this case, the factors are 3 and 5. 3 x 5 = 15

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!! The velocity of sound in air is given by the equation , where v is the velocity in meters per second and t is t
jeyben [28]

The equation of velocity of sound in air is v = 20 √(273 + t). In this problem, we need to find the temperature when the velocity is 329 meters/s. You need to measure the time it takes a sound to travel a measured distance in order to measure its speed in air.

 

Given:

Velocity of sound in air equation = v = 20 √(273 + t)

Velocity = 329 m/s

 

To solve:

V = 20 √(273 + t)

<span>
329 = 20 * sqrt(273 + t)</span>

<span>
16.45 = sqrt(273 + t)</span>

<span>
273 + t = 16.45^2</span>

<span>
t- 16.45^2-273</span>

<span>
t = -2.4 degrees Celsius</span>

 

<span>So, the temperature when the velocity is 329 meters per second is -2.4 degrees Celsius.</span>

3 0
3 years ago
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