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3 years ago

How many times greater is the value of the 2 in 420,300 than the value of the 2 in 65,126

2 answers:

5 0

The value of the 2 in 420,300 is in the ten thousands spot and the value of the 2 in 65,126 is in the tens spot. The first 2 is 1000 times greater than the second.

LUCKY_DIMON [66]3 years ago

4 0

Answer:

value of 2 in 420,300 in 1000 times greater than value of 2 in 65,126.

Step-by-step explanation:

The given number is 420,300 in which the place of 2 is at ten thousand.

So the value of 2 in 420,300 is = 20,000

Now in second number 65,126, place of 2 is tenth place.

So value of 2 in 65,126 is = 20

so ratio of 20,000 and 20 = $\frac{20,000}{20}$ = 1,000

Therefore, value of 2 in 420,300 in 1000 times greater than value of 2 in 65,126.

You might be interested in

What is 7x7-3+6-2 when rounded to the nariest 10000

ivanzaharov [21]

Answer:

50.0000

Step-by-s

7 0

3 years ago

Read 2 more answers

Write the equation of the mirror line for the segment with endpoints (5, 4) and (-1, -1).

Kobotan [32]

The equation of the mirror line in standard form is: 10y+12x=39. The reflection of the point is A'(1,2)

Step-by-step explanation:

Given that the endpoints of the segments are: (5,4) and (-1,-1) then the equation of the mirror line will be;

slope=m=Δy/Δx

Δy= -1 - 4= -5

Δx= -1-5 = -6

m= -5/-6 = 5/6

For the equation, taking point (5,4), and (x,y), it will be;

m=Δy/Δx

5/6= y-4/x-5

5(x-5) = 6(y-4)

5x-25 =6y-24

5x=6y-24+25

5x=6y+1

5x-1=6y

6y=5x-1 -------divide both sides by 6

y=5/6x -1/6 -------Equation of line segment

The mirror line is a perpendicular bisector of the segment.This means it passes at the midpoint of the segment.

Finding the midpoint of the segment will be;

{(x₁+x₂)/2 ,(y₁+y₂)/2}

{(5+-1)/2, (4+-1)/2} =(4/2, 3/2) =(2, 3/2)

Using the coordinate point of the midpoint, you can find the equation of the mirror line knowing that the slope will be -6/5 because the mirror line is perpendicular to the line segment that has a slope of 5/6.

Finding the equation of the mirror line using point (2, 3/2), (x,y) and m= -6/5

$\frac{y-1.5}{x-2} =\frac{-6}{5} \\\\5(y-1.5)=-6(x-2)\\5y-7.5=-6x+12\\5y-\frac{15}{2} =-6x+12\\\\10y-15=-12x+24\\\\10y+12x=15+24\\\\10y+12x=39$

The equation of the mirror line in standard form is;

10y+12x=39

2. Given point A(3,-2) and line y=1/2x -1 ,you can use a graph tool to plot the equation for the mirror line, plot the object point and locate the image point across the mirror line.

From the graph, the image is A'(1,2)

Learn More

Reflection of a point :brainly.com/question/12865568

Keywords : equation, mirror line, segment, endpoints, reflection

#LearnwithBrainly

5 0

3 years ago

Read 2 more answers

A doughnut shop sells 30 kinds of doughnuts. in how many ways can you (a) get a bag of 12 doughnuts?

Norma-Jean [14]

Answer:

there are 86493225 possible ways you can get a bag of 12 doughnuts

Step-by-step explanation:

since we do not care about the order of the donuts in the bag ,we will need to calculate the number of possible combinations for 30 different elements in a group of 12 , then:

Number of combinations=C= n! /[(n-r)!*r!]

where n= number of elements , r= group size

replacing values

C= n! /[(n-r)!*r!] = 30!/[(30-12)!*12!] = 86493225 possible combinations

6 0

3 years ago

Please please help me out!!!!!

NeX [460]

Answer:

see explanation

Step-by-step explanation:

By the rational root theorem, any rational roots of f(x) are expressible in the form

$\frac{p}{q}$ for integers p and q

with p a divisor of the constant term 6 and q a divisor of the leading coefficient 1.

The possibilities are ± 1, ± 2, ± 3, ± 6

Since the lead coefficient is 1 dividing by that number doesn't change a thing.

Thus the possible rational roots are

$\frac{p}{q}$ = - 6, - 3, - 2, -1, 1, 2, 3, 6

6 0

3 years ago

A pebble is dropped into a deep well and 3s later the sound of a splash is heard as the pebble reaches the bottom of the well. T

ankoles [38]

Answer:

$2.89\ \text{s}$

0.11 seconds

$37.4\ \text{m}$

Step-by-step explanation:

$t_1$ = Time taken by the pebble to hit the water

$t_2$ = Time taken by the sound to travel to the observer

$t_1+t_2$ = Time taken by the observer to listen to the splash after stone is thrown = 3 s

$t_1=3-t_2$

a = g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

$u_s$ = Speed of sound = 340 m/s

The distance traveled by the pebble

$s=ut+\dfrac{1}{2}at_1^2\\\Rightarrow s=0+\dfrac{1}{2}\times9.81(3-t_2)^2\\\Rightarrow s=4.905(9+t_2^2-6t_2^2)$

Distance traveled by the sound

$s=u_st\\\Rightarrow s=340\times t_2$

The distance traveled by the sound and the pebble is equal

$4.905(9+t_2^2-6t_2)=340\times t_2\\\Rightarrow 9+t_2^2-6t_2=\dfrac{340}{4.905}t_2\\\Rightarrow 9+t_2^2-6t_2=69.32t_2\\\Rightarrow t_2^2-75.32t_2+9=0\\\Rightarrow t_2=\frac{-\left(-75.32\right)\pm \sqrt{\left(-75.32\right)^2-4\times \:1\times \:9}}{2\times \:1}\\\Rightarrow t_2=75.2,0.11$

Since $t_1+t_2=3$ the value of $t_2$ cannot be greater than 3.

So, time taken by the sound to reach the observer is 0.11 seconds.

Time taken by the pebble to hit the water is $t_1=3-t_2=3-0.11=2.89\ \text{s}$

Depth of the well is $s=340t_2=340\times 0.11=37.4\ \text{m}$

8 0

3 years ago