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2 years ago

Please answer this correctly. if its spam or wrong i report correct you get brainliest

Mathematics

1 answer:

kvasek [131]2 years ago

3 0

The Domain is the X values and the range is the Y values

Looking at where the 3 dots are located, the X's are -3, 0 and 2 and the Y's are 3, 0 , -2

Domain{-3,0,2} range {3,0,-2}

The answer would be A.

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2/3 as a real number

BaLLatris [955]

Answer:

Yes

Step-by-step explanation:

I don't know the question but 2/3 is a real number.

8 0

3 years ago

What is the area of the regular trapezoid below? - 6 cm T 8 cm 10 cm

Elenna [48]

Answer:

Area = 64 cm²

Step-by-step explanation:

To find the area, we have to follow some steps:

=> Step 1: Make the bases similar:

Since we have 2 bases given 6 and 10 we have to come up with a third base by finding their average:

(6 + 10) / 2

(16) / 2

So now that we know our base,

=> Our second step is to multiply the base we found by the height of the trapezoid:

Area = common base * height

Area = 8 * 8

Area = 64 cm²

Hope this helps!

5 0

2 years ago

Help with 6th grade math!

Naya [18.7K]

I can answer most of them!

4 0

3 years ago

Read 2 more answers

Given a and b are first quadrant angles, sin a=5/13 and cos b=3/5 evaluate sin (a-b)1) -33/652) 33/653) 63/65

bezimeni [28]

The correct option is -33/65.

The solution is given below:

5 0

7 months ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$

Follow the above procedure will give the vertex form.

(NOTE : you must know that $\mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}$ . Use this equation in transforming the equation from step 3 to step 4)

8 0

3 years ago