Where is the point of concurrency of the angle bisectors of a triangle?
1 answer:
Answer:
The point of concurrency of the angle bisectors of a triangle is inside the triangle.
Step-by-step explanation:
Considering the triangle ΔABC as shown in attached figure.
As it is clear that
- The three angle bisectors of a triangle intersect at one point.
- Incenter is basically the point of concurrency of the angle bisectors.
- Each point on the angle bisector is at equal distance from the sides of the angle.
As the triangle's incenter is always located inside the triangle, so we can conclude that the point of concurrency of the angle bisectors of a triangle is inside the triangle.
Therefore, the point of concurrency of the angle bisectors of a triangle is inside the triangle
Please check the attached figure below.
Keywords: angle bisectors of a triangle, point of concurrency
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If your looking for Standard Form Rewrite it as...
The probability distribution for the face landing down = 4/15
<h3>What is the probability?</h3>The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.
<h3>According to the given information:</h3>If we assign 1 probability x
then 2 has probability 1/2 x.
Similarly,
then 3 has probability = 1/2((1/2)*x) = (1/4)*x
so
then 4 has probability = 1/2((1/4)*x) = (1/8)*x
These probabilities need to sum to 1.
Hence:
or equivalently
(15/8)*x = 1
x = 8/15
the probability distribution for the face landing down = (1/2)*(8/15)
= 8/30
= 4/15
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I understand that the question you are looking for is:
A tetrahedral die has four faces, numbered 1-4. If the die is weighted in such a way that each number is twice as likely to land facing down as the next number (1 twice as likely as 2, 2 twice as likely as 3, and so on) what is the probability distribution for the face landing down?