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3 years ago

Please please I’m beginning you!

Mathematics

1 answer:

VikaD [51]3 years ago

6 0

Answer:

Soccer: 30,000 fans

Golf: 60,000 fans

Tennis: 135,000

Basketball: 225,000

Football: 330,000

Hockey: 720,000

Step-by-step explanation:

I think making the circle graph is self explanatory, sorry, I can't show it.

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Evaluate the limit of lim/n->infinity 6n^2+5/3n^2

castortr0y [4]

we are given

$\lim_{n \to \infty} \frac{6n^2+5}{3n^2}$

we can see that

degree of numerator = degree of denominator =2

so, we can divide both numerator and denominator by n^2

and we get

$\lim_{n \to \infty} \frac{(6n^2+5)/n^2}{(3n^2/n^2)}$

$\lim_{n \to \infty} \frac{(6n^2/n^2)+(5/n^2)}{(3n^2/n^2)}$

now, we can simplify it

$\lim_{n \to \infty} \frac{6+(5/n^2)}{3}$

now, we can plug n=inf

$= \frac{6+(5/(\infty))}{3}$

$= \frac{6+0}{3}$

$= \frac{6}{3}$

$= 2$ ...............Answer

6 0

3 years ago

Read 2 more answers

The ratio of Ali's mass to John's mass is 6:5. The ratio of John's muss

djverab [1.8K]

Step-by-step explanation:

The ratio of Ali mass to Williams mass is

6 : 3

= 2 : 1

Option 2 is the correct answer

5 0

3 years ago

A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the prob

UkoKoshka [18]

Answer:

The probability that 8 mice are required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

$P(X=r)=^nC_r p^rq^{n-r}$

Where, p is the probability of success $p=\frac{2}{7}$

q is the probability of failure q=1-p, $q=1-\frac{2}{7}=\frac{5}{7}$

n is total number of trials n=8

r=3

Substitute the values,

$P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}$

$P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}$

$P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}$

$P(X=3)=0.2428$

Therefore, the probability that 8 mice are required is 0.2428.

5 0

3 years ago

One of the x-intercepts of the parabola represented by the equation y = 3x^2 + 6x − 10 is approximately (1.08, 0).

Igoryamba

3x^2 + 6x - 10 = 0

x = [-6 +/- sqrt(^2 - 3*3*-10)] / 2*3

= 1.08 and -3.08

Other x -intercept is (-3.08,0)

4 0

3 years ago

Read 2 more answers

B= c= Please help asap

gladu [14]

B= 20°
and c = 160°

b is equal to the given angle, b = 20°

c is 180 - 20 = 160°

4 0

2 years ago