I am not sure if I understand the question that clearly but if what I think is correct is that you need to prove that 2 and 1 are a system of equations for the following equations so this is how you do that:
With the coordinates (2,1) 2 will be x and 1 will be y because when dealing with coordinates (x,y) is how they are set up.
Next you substitute into the equations and solve:
(2) + 3(1) = 5 and 1 = -(2)+3
So now you find if the equations are true
2 + 3 = 5 so (2,1) is a solution for this equation
-2 + 3 = 1 so (2,1) is also a solution for this equation
So in conclusion (2,1) is a solution of the system of equations
Hope this helps :)
D(AB) = <span>√(6-0)^2 +(3-0)^2
d(AB) = </span><span>√36+9
d(AB) = </span><span>√45
d(AB) = 3</span><span>√5
or
d(AB) = 6.71
hope it helps</span>
Answer:
r = 1/11
Step-by-step explanation:
16r-2r = -3r+6r+1
14r = 3r+1 (combine like terms)
11r = 1
r = 1/11
Answer:
{x = -3 , y = 4 , z = 0
Step-by-step explanation:
4x ≤ 12
x ≤ 3 <em>divided both sides by 4</em>
Graph: ←--------------------3 <em>(fill in the dot at 3 since it is "equal to")</em>
Interval Notation: (-∞, 3]
Answer: x ≤ 3
