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Usimov [2.4K]
3 years ago
13

ANSWER ASAP BRANLIEST TY​

Mathematics
1 answer:
slava [35]3 years ago
6 0

Answer:

x = 3

y = 1

Domain: x < 3 U x > 3

Range: y < 1 U y > 1

Step-by-step explanation:

Vertical asymptote: x = 3

Horizontal asymptote: y = 1

Domain: x < 3 U x > 3

Range: y < 1 U y > 1

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Emily can write 1/6 pages for Ms.McCrimmon in 1/12 minutes. What was her unit rate to write full pages?
Vinil7 [7]

1/6:1/12 is 2:1

She can write 2 pages per minute

3 0
3 years ago
The operation denoted is by * is commutative and why?​
kipiarov [429]

Answer:

The commutative property of multiplication states that changing the order of the numbers we are multiplying, does not change the product.

3 0
3 years ago
Read 2 more answers
A prism, bases of which are equilateral triangles, circumscribes a sphere of radius 6. What is the volume of the prism?
koban [17]

Answer:

  1296√3 cubic units

Step-by-step explanation:

The volume of the prism will be the product of its base area and its height. Since it circumscribes a sphere with diameter 12, that is the height of the prism.

The central cross section of the sphere is a circle of radius 6, and that will be the size of the incircle of the base. That is, the base will have an altitude of 3 times that incircle radius, and an edge length of 2√3 times that incircle radius. Hence the area of the triangular base is ...

  B = (1/2)(6×2√3)(6×3) = 108√3 . . . . . square units

The volume of the prism is then ...

  V = Bh = (108√3)(12) = 1296√3 . . . cubic units

_____

<em>Comment on the geometry</em>

The centroid of an equilateral triangle is also the incenter and the circumcenter. The distance of that center from any edge of the triangle is 1/3 the height of the triangle. So, for an inradius of 6, the triangle height is 3×6 = 18. The side length of an equilateral triangle is 2/√3 times the altitude, so is 12√3 units for this triangle.

6 0
4 years ago
The equation of line A is y = 7x + 12. Line B is perpendicular to line A and passes through the point . What would be the soluti
max2010maxim [7]
Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
1) y=7x+12
2)y=-(1/7)x+c

In this simultaneous equation we see that y is equal to both the expressions. So,
7x+12=-(1/7)x+c

Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)
3 0
3 years ago
Evaluate the following equation: integral from 3 to infinity: 1/(x-2)^(3/2) dx
Bond [772]

The formula in solving the integral of the infinity of 3 is  ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>

Substitute the numbers given then solve

limn→inf∫3n(1/((n−2)(3/2))dn

limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)

=0+2=2

 

Solve for the integral of 2 when 2 is approximate to 0. Transpose 2 from the other side to make it -2

∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C

(x−2)−1/2=1x−2−−−−√

0−(3−2)−1/2−1/2=2

<span> </span>

8 0
4 years ago
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