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MAVERICK [17]
2 years ago
15

Is 5/10 equivalent to 1/6​

Mathematics
2 answers:
Citrus2011 [14]2 years ago
8 0

Answer:

No, its not equivalent

1/2 is equivalent though

Please mark as brainliest

galben [10]2 years ago
3 0

Answer:

No

Step-by-step explanation:

Given the following question:

\frac{5}{10}

You can prove 5/10 isn't equivalent to 1/6 by simply reducing 5/10.

\frac{5}{10}
\frac{5}{10}\div5=\frac{1}{2}
=\frac{1}{2}
\frac{1}{2} > \frac{1}{6}

5/10 isn't equivalent to 1/6, so your answer is "no."

Hope this helps.

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Alex17521 [72]
C is the corret answer 
5 0
3 years ago
Read 2 more answers
What are the coordinates of point B on \overline{AC} such that AB = 1/2 BC
marta [7]

Answer:

C. B(x,y) = \left(3,-\frac{16}{3} \right)

Step-by-step explanation:

Let A(x,y) = (6,-7), B(x,y) = (x,y) and C(x,y) = (-3,-2). From statement we know that AB = \frac{1}{2}\cdot BC, which is equivalent to the following linear algebraic formula:

B(x,y) -A(x,y) = \frac{1}{2}\cdot [C(x,y)-B(x,y)] (1)

B(x,y)-A(x,y) = \frac{1}{2}\cdot C(x,y)-\frac{1}{2}\cdot B(x,y)

\frac{3}{2}\cdot B(x,y) = \frac{1}{2}\cdot C(x,y)+A(x,y)

B(x,y) = \frac{1}{3}\cdot C(x,y) +\frac{2}{3}\cdot A(x,y) (2)

Then, the coordinates of point B on AC are:

B(x,y) = \frac{1}{3}\cdot (-3,-2)+\frac{2}{3}\cdot (6,-7)

B(x,y) = \left(-1, -\frac{2}{3}\right)+\left(4, -\frac{14}{3} \right)

B(x,y) = \left(3,-\frac{16}{3} \right)

Which means that correct answer is C.

5 0
3 years ago
Carlos dropped the phone he had received for his birthday and broke the screen. He knows he has to pay for the replacement himse
kiruha [24]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Which expression is equivalent to the following complex fraction? <br><br>(pls help me out)​
const2013 [10]

Answer:

B. \frac{-4x + 7}{2(x - 2)}

Step-by-step explanation:

Simplify the given expression to determine its equivalent expression in the given options.

\frac{\frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1}}

\frac{\frac{3}{x - 1} - \frac{4}{1}}{\frac{2}{1} - \frac{2}{x - 1}}

\frac{\frac{3 - 4(x - 1)}{x - 1}}{\frac{2(x - 1) - 2}{x - 1}}

\frac{\frac{3 - 4x + 4}{x - 1}}{\frac{2x - 2 - 2}{x - 1}}

\frac{\frac{-4x + 7}{x - 1}}{\frac{2x - 4}{x - 1}}

\frac{-4x + 7}{x - 1} * \frac{x - 1}{2x - 4}

(x - 1) cancels (x - 1)

\frac{-4x + 7}{1} * \frac{1}{2x - 4}

\frac{(-4x + 7)1}{1(2x - 4)}

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\frac{-4x + 7}{2(x - 2)}

3 0
3 years ago
Circle area of a radius of 3
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Answer:

A=28.27

Step-by-step explanation:

8 0
3 years ago
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