let's firstly convert the decimal to a fraction, namely a rational.
so we have one decimal, thus let's use 1 zero at the denominator and lose the dot on the numerator.

so then, what rationals are between -8/5 and +8/5? well, a huge amount hmmm let's pick two.
![\bf \boxed{-\cfrac{8}{5}}\rule[0.35em]{9.5em}{0.25pt}~~-\cfrac{3}{5}~~\rule[0.35em]{2em}{0.25pt}0\rule[0.35em]{10em}{0.25pt}~~\cfrac{6}{5}~~\rule[0.35em]{2.5em}{0.25pt}\boxed{\cfrac{8}{5}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cboxed%7B-%5Ccfrac%7B8%7D%7B5%7D%7D%5Crule%5B0.35em%5D%7B9.5em%7D%7B0.25pt%7D~~-%5Ccfrac%7B3%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D~~%5Ccfrac%7B6%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2.5em%7D%7B0.25pt%7D%5Cboxed%7B%5Ccfrac%7B8%7D%7B5%7D%7D)
Answer:
2/3 min
Step-by-step explanation:
We can write these as equations
so 8-2.5x=5-0.5x
We isolate x by subtracting both sides by 5
3-2.5x=0.5x
add 2.5x to both sides
3=2x
divide both sides by 2
x=2/3min
(plz give brainliest)
Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer