All categories

3 years ago

If AB=3 and BC=7,then AC=?

Mathematics

2 answers:

Pie3 years ago

7 0

Answer:

AC = 10

Step-by-step explanation:

AB = 3

BC = 7

3 + 7 = 10

AC = 10

Salsk061 [2.6K]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

If 2x+7 over 4 =5, what is the value of 6x

jekas [21]

Answer:

(2x+7)/4=5

2x+7 = 20

2x= 20-7

2x = 13

x = 13/2

6x =13/2×6

=13×3

=39

4 0

3 years ago

Suppose that 24% of the students in the first group answered yes and that 73% of the students in the second group answered yes.

Lera25 [3.4K]

Answer:

Price Discrimination OR Law of Demand; according to the complete question.

Step-by-step explanation:

24% of the students in the first group answered yes.

73% of the students in the second group answered yes.

More students in the second group were willing to pay $75 for the pair of jeans BECAUSE they were told that the normal price was much higher.

From this information, I guess that the first group was told (by the jeans vendor probably) that the $75 was higher than the normal price of the jeans. This will be the reason why a lesser percentage of students in Group A are willing to purchase the pair of jeans.

This is an example of PRICE DISCRIMINATION effect on decision making. Price discrimination is used in product marketing.

The same pair of jeans in Situation A cost higher than the normal price while in Situation B it cost lower than the normal price. Even though the figure given is static at $75 in both cases, the data that follows in the question tells it as 2 different prices; one favourable to the buyers and another not so favourable to the buyers.

The LAW OF DEMAND also applies here. The higher the price, the lesser the quantity demanded (by a group of students) and the lower the price, the higher the quantity demanded.

5 0

3 years ago

4(2x - 1) + 2x + 2 = 28

lara31 [8.8K]

Answer:

x=3

Step-by-step explanation:

isolate the variable by dividing each side by factors that dont contain the variable

3 0

3 years ago

Read 2 more answers

Which statement represents the expression?

ipn [44]

Answer:

Which statement represents the expression?

24−8÷4

<u>A.</u><u> </u><u>24 minus 8 divided by 4</u>

B. the difference of 24 and 8 divided by 4

C. 24 minus the quotient of 8 divided by 4

D. 24 minus 4 divided by 8

The answer is <em><u>a. 24 minus 8 divided by 4</u></em>

-----------------------------------

$\green{ \boxed{ \boxed{ \sf{Lusi \: Adriana} } } }$

<h3 /><h3>Hope it is useful...</h3>

7 0

3 years ago

Question: An airport deli sells turkey, ham, and roast beef sandwiches. A customer can choose between turkey,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle \frac{1}{12}$ .

Step-by-step explanation:

Ginger selects the ingredients randomly. Therefore, the choices she makes would be independent. In other words, her choice of cheese (and mayonnaise) won't depend on what she chose for meat. Therefore:

$\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise})\end{aligned}$ .

It is worth noting that this equality would not be valid if the choices are not independent. For example, if Ginger is more likely to choose mayonnaise after choosing cheese, then $P(\text{(roast beef) and (cheese) and (no mayonnaise)})$ and $P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise})$ would likely be different.

What is the probabilities that Ginger would select roast beef for the sandwich? The question states that Ginger is "equally likely" to select each of turkey, ham, and roast beef. In other words:

$P(\text{roast beef})= P(\text{turkey}) = P(\text{ham})$ .

At the same time, Ginger has to choose exactly one of these options. She can't choose no meat of more than one options at a time. Therefore:

$P(\text{roast beef})+ P(\text{turkey}) + P(\text{ham}) = 1$ .

Combine these two equations to conclude that:

$\displaystyle P(\text{roast beef}) = \frac{1}{3}$ .

Similarly, Ginger has to choose between cheese or no cheese, and mayonnaise or no mayonnaise. Therefore:

$\displaystyle P(\text{cheese}) = \frac{1}{2}$ .
$\displaystyle P(\text{mayonnaise}) = \frac{1}{2}$ .

Back to the probability for roast beef, cheese, and no mayonnaise:

$\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise}) \\ &= \frac{1}{3} \times \frac{1}{2} \times \frac{1}{2} \\ &= \frac{1}{12}\end{aligned}$ .

8 0

4 years ago