What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2
x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic
x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3
5x - 3 = 0
No it is not a quadratic because it does not have x^2
2x^2 + 12x = 0
Yes because there's x^2
5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2
9x^2 + 6x - 3 = 0
Yes because there's x^2
Answer:
2
Step-by-step explanation:
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Answer:
y = 5
Step-by-step explanation:
<u>Step 1:</u>
(18) -7y = -17
-18 -18
<u>Step 2:</u>
-7y = -35
÷-7 ÷-7
y = 5
S=i(n-1)+2*(n-1)+1 perhaps
