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2 years ago

How much p² – q² + 2pq is less than -2p² -2q² + 7pq +10 ?

Mathematics

1 answer:

ValentinkaMS [17]2 years ago

6 0

Answer: 3p² + q² - 5pq - 10 < 0

<u>Step-by-step explanation:</u>

p² - q² + 2pq < -2p² - 2q² + 7pq + 10

since you didn't specify what to solve for, move everything from the right side to the left side of the inequality symbol using inverse operations.

(p² + 2p²) + (- q² + 2q²) + (2pq - 7pq) + (- 10) < 0

3p² + q² + -5pq + -10 < 0

3p² + q² - 5pq - 10 < 0

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Step-by-step explanation:

use the Pythagorean theorem.

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3 years ago

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makkiz [27]

$f(t)=h=-16t^2+20t+6

$

a=-16, b=20, c =6

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max:

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3 years ago

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