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Natasha_Volkova [10]
3 years ago
8

Under her cell phone plan, Lily pays a flat cost of $55.50 per month and $4 per

Mathematics
2 answers:
TEA [102]3 years ago
8 0

Answer:

Equation : y = 4x + 55.50

x = 1.9 gigabytes

Step-by-step explanation:

Given that:

Flat fee per month = $55.50

Cost per gigabyte = $4

Let,

x be the number of gigabytes.

y be the total cost

y = 4x + 55.50

Lily wants to keep her bill $63.10

63.10 = 4x + 55.50

63.10 - 55.50 = 4x

4x = 7.60

Dividing both sides by 4

\frac{4x}{4} = \frac{7.60}{4}\\x=1.9

Hence,

Equation : y = 4x + 55.50

x = 1.9 gigabytes

LuckyWell [14K]3 years ago
3 0

Answer:

Equation: 4x+55.5=63.1

Answer: x=1.9

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What is the axis of symmetry of the function f(x) = –(x + 9)(x – 21)?
ludmilkaskok [199]
First, we have to realize that this is factored form, so we have to put this in standard quadratic form using FOIL, which is a rule mandating how we multiply the numbers here. F stands for First, which means the first number inside the parentheses for both of them, then O means the first number in the first quantity(fancy word for parentheses) multiplied by the last number of the second quantity, and so forth. When you are done, you combine like terms

anyway, you end up with x²-12x-189, but you have to inverse all numbers because of the parentheses in front, so it becomes -x²+12x+189.

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3 years ago
What is the area?? Please help
Olegator [25]

Answer:

<h3>324 ft²</h3>

Step-by-step explanation:

We have the triangle and the rectangle.

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A_{\triangle}=\dfrac{1}{2}bh

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A_{\boxed{\ }}=lw

l - length

w - width

We have b = 24 ft, h = 7 ft, l = 24 ft and w = 10 ft.

Substitute:

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Solving for matrices
muminat

Answer:

D

Step-by-step explanation:

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)

Subtract the third row from the second:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)

Divide the third row by 6:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)

You get the system of three equations:

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