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2 years ago

Help me please

Mathematics

1 answer:

Alika [10]2 years ago

8 0

Answer:

Step-by-step explanation:

Because neither Mr. Kim nor anyone else is picking the people of a specific group when the paper is drawn from the bag. And rolling a cube with numbers 1-6 you almost never get the number you want so it is really random. And then after the groups are picked they roll the die and then that number is crossed off so it is not used again with the other groups.

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likoan [24]

It's easy to show that $7\tan(4x)$ is strictly increasing on $x\in\left[0,\frac\pi8\right]$ . This means

$M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3$

and

$m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7$

Then the integral is bounded by

$\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)$

$\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}$

7 0

2 years ago

Which expression can be added to the right side of the equal sign form an equation? 8•7 - 4=

valentina_108 [34]

left side = 52

9*5 + 7 = 52

So its C.

6 0

3 years ago

Read 2 more answers

uppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76 c

r-ruslan [8.4K]

Significant figures and decimal places are different things. If this were to be rounded to 2 DP you would be right, however Significant figures are to do with units. In this case, it would be 12cm^2

5 0

4 years ago

Would appreciate it very much if you could help me :D

BARSIC [14]

Answer:

<h2>Hope it helps you......</h2>

8 0

3 years ago

Simplify the following <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Cfrac%7B1%7D%7Bx%7D%20%20%2B%201%20%7D%20%7B%20%5Cfrac%2

Anon25 [30]

Good evening, Riley!

Used properties:

$\star~\boxed{\mathsf{a = \dfrac{ax}{x}, \ \ x\neq 0}}\\ \\ \\ \star~\boxed{\mathsf{\dfrac{\frac{a}{b}}{\frac{c}{d}} = \dfrac{ad}{bc}}}$

Now, note that:

$\mathsf{1 = \dfrac{x}{x},\ x\neq 0}$

So:

$\mathsf{\dfrac{\frac 1 x + \frac x x }{\frac 1 x} = \dfrac{\frac{x+1}{x}}{\frac 1 x}}=} \mathsf{\dfrac{x}{1}\dfrac{x+1}{x} = \boxed{x + 1}}$

8 0

3 years ago