All I know for sure is that the first one is an inequality
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
Answer:
21 liters of the 12% solution and 4 liters of the 37% solution
Step-by-step explanation:
Represent the number of liters of the first solution as x and the second as y. Now, the total liters of iodine is going to be 16% of 25 = 4 liters of iodine, and the total liters of each solution is going to be 25. Now, we can setup two equations:
0.12x+0.37y = 4
x + y = 25
Multiplying the bottom equation by 0.12, we have
0.12x + 0.12y = 3
Subtracting, we have
0.12x+0.37y=4
-
0.12x + 0.12y = 3
= 0.25y = 1
= y = 4
= x = 25 - 4 = 21
8x = 44 -4
8x = 40
x = 40/8
x = 5
