What is the situation from the problem
Answer:
Look in the file, I've drew it there!
Answer:
Step-by-step explanation:
T(1)=1=0*x^3 0*x^2 0*x 1*1 T(x)=x-1=0*x^3 0*x^2 1*x (-1)*1 T(x^2)=2x^2-6x 6=0*x^3 2*x^2 (-6)*x 6 T(x^3)=6x^3-48*x^2 141*x-141 T(x^4)=24*x^3-204*x^2 628*x-604*1 collect the coefficient matrix and take its transpose
0 0 0 6 24
0 0 2 -48 -204
0 1 -6 141 628
1 -1 6 -141 -604
Answer:
n=9
Explanation:
First, let's give a name to the number we are looking for and call it n.
So we can then write "A number is divided by 3" as n3
To add 5 to the quotient would then give us the expression n3+5
If this results in 8 we can finally write the equation we are trying to solve and solve the equation for n while keeping the equation balanced:
n3+5=8
n3+5−5=8−5
n3+0=3
n3=3
3⋅n3=3⋅3
1n=9
n=9
