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1 year ago

1. Graph the equation y = 5/4 X - 10 using the y-intercept point and slope. HELP ME PLEASE

Mathematics

1 answer:

iren [92.7K]1 year ago

7 0

The slope is m=5/4 and the y-intercept is b= -10

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Solve 5n – 7p + 3n = 25p for n.

saul85 [17]

5n – 7p + 3n = 25p

Combine like terms

8n - 7p = 25p

Add (7p) to both sides

8n - 7p + 7p = 25p + 7p

Simplifying

8n = 32p

Divide both sides by 8

8n / 8 = 32p / 8

Simplifying

n = 4p

7 0

3 years ago

Read 2 more answers

If a line has a slope of -4 and a u intercept of 1, which of the following is it's graph?

3241004551 [841]

Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing

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2 years ago

How many 1 2/3 cup servings are in 15 1/4 cups of salsa

lilavasa [31]

Answer:

9.18

Step-by-step explanation:

1.66/15.25=9.18

6 0

2 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago

Quasim ordered 32 cases with 28 cans of fruit in each case. He also received 24 cases with 13 large cans of fruit in each case.

klasskru [66]

I am assuming the 32 cases contain the small cans...

32 cases...with 28 small cans of fruit in each case..
32 * 28 = 896 small cans of fruit in total

24 cases...with 13 large cans of fruit in each case...
24 * 13 = 312 large cans of fruit in total

so there are (896 - 312) = 584 more small cans then large cans <==

8 0

2 years ago