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JulijaS [17]
3 years ago
15

A researcher decides to determine if the type of writing utensil that a student uses while doing their math affects their accura

cy. A group of 1200 high school students in Algebra are randomly divided into four groups. One group uses a regular pencil, another uses a mechanical pencil, one group uses a pen and the fourth group is allowed to use whatever type of utensil they feel like. A math test is given and the results are tabulated for accuracy. The variable- type of writing utensil - is what type of variable?
Mathematics
1 answer:
alexandr1967 [171]3 years ago
5 0

Since the variable type of writing utensil assumes labels and not numbers, it is classified as qualitative.

<h3>What are qualitative and quantitative variables?</h3>
  • Qualitative variables: Assumes labels or ranks.
  • Quantitative variables: Assume numerical values.

In this problem, the type of writing utensil has 4 labels: regular pencil, mechanical pencil, pen, whatever.

Hence, since the variable assumes labels and not numbers, it is classified as qualitative.

More can be learned about quantitative and qualitative variables at brainly.com/question/20598475

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I believe its B.

Step-by-step explanation:

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determine the slope of the line that contains the points g(8,1) &amp; h(8,-6). select one: a. 2 b. 5 c. 0 d. undefined
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What is 2a-3 when a=6
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When a=6,

2a - 3 = 2(6) - 3 = 12 - 3 = <em><u>9</u></em>
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Jing- sheng made a scaled copy of the following rhombus. He used a scale factor greater than 1. What could be the side length of
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See below.

Step-by-step explanation:

You don't provide the original side length, but since the scale factor is greater than 1, all correct answers are lengths that are greater than the original side length.

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"What is the probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice? Assume you’re throwing a single d
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Answer:

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

Step-by-step explanation:

For each throw, there are only two possible outcomes. Either it is a '3', or it is not. This means that we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

There are 6 possible outcomes for the dice. This means that the probability that it is a '3' is \frac{1}{6} = 0.167

There are 10 throws, so n = 10.

Probability of throwing AT LEAST two ‘3’s on the dice?

Either you throw less than two, or you throw at least two. The sum of the probabilities of these events is 1. So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2).

In which

P(X < 2) = P(X = 0) + P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.167)^{0}.(0.833)^{10} = 0.1609

P(X = 1) = C_{10,1}.(0.167)^{1}.(0.833)^{9} = 0.3225

So

P(X < 2) = P(X = 0) + P(X = 1) = 0.1609 + 0.3225 = 0.4834.

Finally:

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4839 = 0.5161.

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

5 0
3 years ago
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