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Ulleksa [173]
2 years ago
5

Find product of (6x^2 +8) (3x^2-5x+7) HELPPP

Mathematics
1 answer:
shusha [124]2 years ago
7 0
The answer is 18x^4 - 30x^3 + 66x^2 - 40x + 56
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Calculate and express your answer in Decimal from 1/2×17
prohojiy [21]

Answer:

8.5

Step-by-step explanation:

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What is the square root of 12 plus the square root of 27?
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−5/6−3/2v+15/4+3/1v what is this equation fully simplified
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6 0
3 years ago
Kate bought 3 used CDs and 1 used DVD at the bookstore. Her friend Joel bought 2 used CDs and 2 used DVDs at the same store. If
natka813 [3]

Answer:

Cost of 1 DVD is $6.5

Cost of one CD is $4.5

Combine cost of one DVD and CD is $11

Step-by-step explanation:

Given :

Kate bought 3 used CDs and 1 used DVD at the bookstore.

Her friend Joel bought 2 used CDs and 2 used DVDs at the same store.

Kate spent $20

Joel spent $22

To Find :  the cost of a used CD and a used DVD

Solution :

Let cost of 1 used CDs be $x

Let cost of 1 used DVDs be $y

Cost of 3 used CDs = $3x

Cost of 2 used CDs = $2x

Cost of 2 used DVDs = $2y

Kate bought 3 used CDs and 1 used DVD at the bookstore.

She spent $20

So, equation becomes :

⇒3x+y=20 ---(a)

Joel bought 2 used CDs and 2 used DVDs. she spent $22.

So, equation becomes:

⇒2x+2y=22 --(b)

Now solve (a) and (b) to determine the value of x and y

We will use substitution method

Substitute the value of x from (b) in (a)

3(\frac{22-2y}{2} )+y=20

33-3y+y=20

33-2y=20

33-20=2y

13=2y

\frac{13}{2} =y

6.5 =y

Thus cost of 1 DVD is $6.5

Now substitute this value of y in b to get value of x

⇒2x+2(6.5)=22

⇒2x+13=22

⇒2x=22-13

⇒2x=9

⇒x=\frac{9}{2}

⇒x=4.5

Thus the cost of one CD is $4.5

Hence the combine cost of one DVD and CD =  $6.5+ $4.5=$11


6 0
3 years ago
Can someone help me plzzzzzzzzz I’m failing math rn
zysi [14]

Answer:

number 1 is b

Step-by-step explanation:

4 0
2 years ago
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