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Trava [24]
3 years ago
7

PLEASE SOLVE ITDONT STEAL POINYS!! ​

Mathematics
1 answer:
Leviafan [203]3 years ago
3 0

Answer:

A) 3

Step-by-step explanation:

<h2>Method 1)</h2>

Ques: 30/(4√3 + 3√2) = 4√3 - a√2

Rationalise the denominator.

→ 30/(4√3 + 3√2) × (4√3 - 3√2)/(4√3 - 3√2) = 4√3 - a√2

→ (120√3 - 90√2)/(48 - 18) = 4√3 - a√2

→ (120√3 - 90√2)/30 = 4√3 - a√2

→ 120√3 - 90√2 = 120√3 - 30a√2

→ 90√2 = 30a√2

On solving we get,

→ a = 3

<h2>Method 2)</h2>

Ques: 30/(4√3 + 3√2) = 4√3 - a√2

→ 30 = 4√3(4√3) + 4√3(-a√2) + 3√2(4√3) + 3√2(-a√2)

Solve the brackets,

→ 30 = 48 - 4a√6 + 12√6 - 6a

→ - 18 = - 4a√6 - 12√6 - 6a

Put like terms on one side,

→ - 18 + 6a = - 4√6 (a + 3)

Take the common,

→ 3(a - 3) = - 2√6 (a + 3)

→ 3 (a - 3) = 2√6 (-a - 3)

→ [3(a - 3)]/2√6 = - a - 3

Rationalise the denominator,

→ 2√6(3a - 9)/24 = - a - 3

→ (3a√6 - 9√6)/12 = - a - 3

→ √6(a - 3) = - 4a - 12

Do squaring on both sides,

→ [√6(a - 3)]² = - (4a + 12)²

→ 6(a² + 9 - 6a) = - (16a² + 144 + 96a)

Solve the brackets,

→ 6a² + 54 - 36a =  - 16a² - 144 - 96a

→ 22a² - 132a + 198 = 0

→ 11a² - 66a + 99 = 0

→ a² - 6a + 9 = 0

Split the middle term,

→ a² - 3a - 3a + 9 = 0

→ a(a - 3) -3(a - 3) = 0

→ (a - 3)(a - 3) = 0

On comparing we get,

→ a = 3 (key to solve this and similar questions is rationalisation of the denominator)

Hence, the correct option is option A) 3.

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