find two consecutive integers such that ten more than twice the smaller is seven less than three times the larger

1 answer:

6 0

This is how I would work it out:

1st no. = x+1 2x+10=3(x+1)-7
2nd no. = x 2x+10=3x-4
x=14

1st no. is 15; 2nd no. is 14

To check: 28+10=38; three times the larger is 45; and 38 is 7 less than 45.

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