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zzz [600]
3 years ago
15

find two consecutive integers such that ten more than twice the smaller is seven less than three times the larger

Mathematics
1 answer:
Radda [10]3 years ago
6 0
This is how I would work it out:

1st no. = x+1                 2x+10=3(x+1)-7
2nd no. = x                    2x+10=3x-4
                                              x=14   

1st no. is 15; 2nd no. is 14 

To check: 28+10=38; three times the larger is 45; and 38 is 7 less than 45.


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