Question

find two consecutive integers such that ten more than twice the smaller is seven less than three times the larger

Answer 1

This is how I would work it out:

1st no. = x+1                 2x+10=3(x+1)-7
2nd no. = x                    2x+10=3x-4
                                              x=14   

1st no. is 15; 2nd no. is 14 

To check: 28+10=38; three times the larger is 45; and 38 is 7 less than 45.