What is the strongest relationship you can infer between two variables from this statement? The number of minutes you can talk o
1 answer:
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Answer:
The distance drive by Lana = 201 miles
The distance drive by Mark = 216 miles
The distance drive by Tony = 67 miles
Step-by-step explanation:
Given as :
The total distance cover by Lana , Tony , Mark = 484 miles
Let The distance drove by Lana = L miles
The distance drove by Tony = T
The distance cover by Mark = M
So , L + T + M = 484 miles
Now, The distance of Tony = of Lana distance
Or, T = × L
And The distance of Mark = 15 + The distance of Lana
Or, M = 15 + L
Now.
L + × L + 15 + L = 484
Or, 2 L + = 484 - 15
Or, 2 L + = 469
Or, = 469
Or, 7 L = 469 × 3
∴ L =
I.e L = 201
The distance drive by Lana = 201 miles
The distance drive by Mark = 15 + L =15 + 201 = 216 miles
The distance drive by Tony = × 201 = 67 miles
Hence The distance drive by each person is
The distance drive by Lana = 201 miles
The distance drive by Mark = 216 miles
The distance drive by Tony = 67 miles Answer
Answer:
a. v(t)= -6.78 + 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)= =
. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒ v' + k
v = g
⇒ [v
]' = g
. Integrating, we have
∫ [v]' = ∫g
v =
+ c
v(t)= + c
.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c = 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78. m/s = - 6.78
+ 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78 + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s