For this case what you should know is that the vector ab will be given by:
ab = b-a
We have then:
ab = (3, 5) - (- 2, 4)
ab = ((3 - (- 2)), (5-4))
ab = (5, 1)
Equivalently the vector is:
ab = 5i + 1j
Answer:
ab = 5i + 1j
Answer:
the point where the two coordinates meet
Step-by-step explanation:
I believe it is 56.55 inches I could be wrong but I tried my best
15,19,26,51,18,21,22,33,31,20,28,19,18
Answer:
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Step-by-step explanation:
Let
S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator
= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators
= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator
= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand
= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor
= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange
= 2(b^2+a^2)/((b+a)^2(b-a))
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3