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pashok25 [27]
2 years ago
13

QUESTION

Mathematics
2 answers:
miss Akunina [59]2 years ago
8 0

Answer:

\frac{1}{3600}

Step-by-step explanation:

400^2 = 160,000

5 2/6 = 32/6 = 16/3

6 70/30 = 250/30 = 25/3

16/3 * 25/3 = 400/9

400/9 / 160,000 = 1/3600

ehidna [41]2 years ago
3 0
The answer should be around 2.778 when the equation is inputted into a calculator.

To visualize in the form of improper fractions:

5 2/3 = 32/6
6 70/30 = 250/30
32/6 * 250/30 / (400)^2 = 2.778
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kvv77 [185]

Answer:

9 total

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Step-by-step explanation:

We have 9 berries

3 are strawberries

9-3 = 6

That leaves 6 to be blueberries

9 total

3 strawberries

6 blueberries

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Dennis stood on a 9 foot ladder to measure the sunflower. How much taller is the tallest sunflower than the ladder?
Shalnov [3]

Answer:

See Explanation

Step-by-step explanation:

Given

Ladder = 9ft

Tallest\ Sunflower = x

Required

How much taller is the tallest

To get this, we simply calculate the difference between the height of the tallest sunflower and the ladder.

i.e.

Difference  = Tallest\ Sunflower - Ladder

Difference  = x - 9

-----------------------------------------------------------------------------------------------------

If for instance, the tallest is 13ft, then it is 4ft taller.

Because:

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4 0
2 years ago
The average weight of the entire batch of the boxes of cereal filled today was 20.5 ounces. A random sample of four boxes was se
zhenek [66]

Answer:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s= 0.286

And then the estimator for the standard error is given by:

SE= \frac{0.286}{\sqrt{4}}= 0.143

Step-by-step explanation:

For this case we have the following dataset given:

20.05, 20.56, 20.72, and 20.43

We can assume that the distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for this case would be:

SE= \frac{\sigma}{\sqrt{n}}

And we can estimate the deviation with the sample deviation:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s= 0.286

And then the estimator for the standard error is given by:

SE= \frac{0.286}{\sqrt{4}}= 0.143

4 0
3 years ago
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