Can someone help me how to solve this please 200/50*17/2*5/17*50
1 answer:
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The values of a and b are a = 33% and b = 43% ⇒ last answer
Step-by-step explanation:
The venn-diagram contains:
- A circle labeled blue 32
- A circle labeled gold 25
- The two circles are overlap with label 12 on the overlap
The table:
→ Band : blue : N.b : total
→ gold : 16% : a : 49%
→ N.g : b : 8% : 51%
→ Total : 59% : 41% : 100%
We need to find the values of a and b
From the table
16% represents the percentage of blue and gold uniforms (2nd row with 2nd column)
From venn-diagram
The common part of blue and gold label with 12 (overlap of two circles)
∴ 16% of the total number of students = 12
∵ 16% × x = 12
∴ × x = 12
∴ 0.16 x = 12
- Divide both sides by 0.16
∴ x = 75
∵ x represents the total number of students
∴ The total number of students were asked is 75
From the table
b represents the percentage of blue but not gold uniforms (3rd row and 2nd column)
From venn-diagram
The part that has blue and not gold labeled with 32 (the part of the blue circle not in the gold circle)
∴ 32 of the total number of students like the blue but not gold
- Divide 32 by the total 75 , then multiply the quotient by 100%
to find the percentage of blue but not gold
∴ b = × 100% = 42.6666%
∴ b ≅ 43%
From the table
a represents the percentage of gold nut not blue uniforms (2nd row and 3rd column)
From venn-diagram
The part that has gold and not blue labeled with 25 (the part of the gold circle not in the blue circle)
∴ 25 of the total number of students like the gold but not blue
- Divide 25 by the total 75 , then multiply the quotient by 100%
to find the percentage of gold but not blue
∴ a = × 100% = 33.3333%
∴ a ≅ 33%
The values of a and b are a = 33% and b = 43%
To check your answer complete the table you will find the total of it is 100% ( for the columns 16% + 43% = 59% , 33% + 8% = 41% , then 59% + 41% = 100%, for the rows 16% + 33% = 49% , 43% + 8% = 51% , then 49% + 51% = 100%)
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Answer:
Step-by-step explanation:
Let the function of quantity in the lung of air be A(t)
So
so, A(t) = Amax sin t + b
A(t) = 2.8t⇒ max
A(t) = 0.6t ⇒ min
max value of A(t) occur when sin(t) = 1
and min value of A(t) = 0
So b = 0.6
and A(max) = 2.2
at t = 2 sec volume of a is 0.6
So function reduce to
and t = 5 max value of volume is represent
so,
when t = 5
so the equation becomes
X=5/9
Y=0.65
See below the following picture for the solution
